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A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra

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A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra  [#permalink]

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New post 04 Mar 2019, 14:23
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A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Francisco, 2,150 miles away, 4 hours later. For the first 2 hours of the trip, the pilot maintains an average speed of 450 miles per hour. If the flight is to arrive as scheduled, what must the plane’s average speed be, in miles per hour, for the next 2 hours?

A. 525
B. 550
C. 600
D. 625
E. 650

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Re: A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra  [#permalink]

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New post 04 Mar 2019, 20:22
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Total distance travelled in first 2 hours = 2*450 = 900 miles..
Distance left 2150-900 = 1250..
Time to reach San Francisco now = 2 hours..
Speed = 1250/2 = 625 mph.

Option D..

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Re: A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra  [#permalink]

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New post 04 Mar 2019, 20:45
First 2 hours: say distance is x miles
s1 = x1/t1 => 450 = x1/2 => x1 = 900 miles
Remaining distance after first 2 hours = 2150-900 = 1250 miles
s2 = 1250/2 = 625 miles per hour (D)
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Re: A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra  [#permalink]

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New post 04 Mar 2019, 22:28
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Solution



Given:
    • A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Francisco, 2,150 miles away, 4 hours later.
    • For the first 2 hours of the trip, the pilot maintains an average speed of 450 miles per hour.

To find:
    • If the flight is to arrive as scheduled, then the plane’s average speed, in miles per hour, for the next 2 hours.

Approach and Working:
Let us assume the average speed of the plane for the next 2 hours is v miles per hour.
    • Distance travelled in the first 2 hours = 450 x 2 = 900 miles
    • Distance travelled in the last 2 hours = v x 2 = 2v miles

As the total distance that needs to be covered is 2150 miles, we can say that
    • 900 + 2v = 2150
    Or, 2v = 2150 – 900 = 1250
    Or, v = 1250/2 = 625 miles per hour

Hence, the correct answer is option D.

Answer: D

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Re: A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra  [#permalink]

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New post 06 Mar 2019, 03:03
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SajjadAhmad wrote:
A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Francisco, 2,150 miles away, 4 hours later. For the first 2 hours of the trip, the pilot maintains an average speed of 450 miles per hour. If the flight is to arrive as scheduled, what must the plane’s average speed be, in miles per hour, for the next 2 hours?

A. 525
B. 550
C. 600
D. 625
E. 650



distance= 2150 miles
speed first 2 hrs = 450 mph
distance covered in 2 hrs = 2*450; 900 miles
distance left = 2150-900 ; 1250 miles
now time to destination 2 hrs
speed should be 1250/2 = 625 mph
IMO D
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Re: A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra  [#permalink]

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New post 08 Mar 2019, 07:59
SajjadAhmad wrote:
A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Francisco, 2,150 miles away, 4 hours later. For the first 2 hours of the trip, the pilot maintains an average speed of 450 miles per hour. If the flight is to arrive as scheduled, what must the plane’s average speed be, in miles per hour, for the next 2 hours?

A. 525
B. 550
C. 600
D. 625
E. 650



We see that total time is 4 hours, and the total distance is 2150 miles.

After 2 hours, the plane has traveled 900 miles, so the plane must travel 2150 - 900 = 1250 miles for the next 2 hours, for an average speed of 1250/2 = 625 mph.

Answer: D
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Re: A plane leaves Chicago at 6 A.M. and is scheduled to arrive in San Fra   [#permalink] 08 Mar 2019, 07:59
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