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MartinMag
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mciatto
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Vicky
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MartinMag
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Great explanation !! :-D Thanks Vicky


The answer is A
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anandnk
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I have a slightly different explaination

if N is a even square-free integer then N/2 has to be odd other wise
it would have a factor which is 4 or square of 2
So we can represent N as 2*m * ( 2n+ 1 )

m is odd and n is either odd or even
so N/2 = m * (2n+1 )
m != 2n+1 because N would then have a square of some odd number
So N/2 is also a square-free integer
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gmatblast
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Yet another approach..

Based on the given definition, a "square-free" number does not have 4, 9, 16, 25, ... as one of the factor.

Now n is even "square-free" number
=> so possible values of n = 2, 6, 10, 14,...

Now go through each of the choices.

n/2 = 1, 3, 5, 7, ..... (ALL "square-free")

remaining all choices will have one of the factors from (4, 9, 16, 25, ...)

So A is the answer.



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