Last visit was: 11 Jul 2025, 14:47 It is currently 11 Jul 2025, 14:47
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
energetics
Joined: 05 Feb 2018
Last visit: 09 Oct 2020
Posts: 298
Own Kudos:
Given Kudos: 325
Posts: 298
Kudos: 906
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
sayan640
Joined: 29 Oct 2015
Last visit: 11 Jul 2025
Posts: 1,223
Own Kudos:
Given Kudos: 783
GMAT 1: 570 Q42 V28
Products:
GMAT 1: 570 Q42 V28
Posts: 1,223
Kudos: 733
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Ravixxx
Joined: 24 Feb 2020
Last visit: 15 May 2025
Posts: 117
Own Kudos:
Given Kudos: 118
Location: Italy
WE:Analyst (Finance: Investment Banking)
Posts: 117
Kudos: 684
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Mizar18
Joined: 28 Jan 2019
Last visit: 06 Jun 2025
Posts: 177
Own Kudos:
Given Kudos: 130
Location: Peru
Posts: 177
Kudos: 264
Kudos
Add Kudos
Bookmarks
Bookmark this Post
1k2,k24 is a number divisible by 3, so 1+2+2+4+2K =multiple of 3:

9+2K= multiple of 3. Since we know that 9 is a multiple of 3, 2K must be also a multiple of 3, so, possible values are:
0, 3,6, and 9.

C) is the answer.
User avatar
Mizar18
Joined: 28 Jan 2019
Last visit: 06 Jun 2025
Posts: 177
Own Kudos:
Given Kudos: 130
Location: Peru
Posts: 177
Kudos: 264
Kudos
Add Kudos
Bookmarks
Bookmark this Post
cf92
Am I the only one who found the question confusing? It asked "how many values could N have" - not K. I understand K can take 4 values, but doesn't any combination of 0, 3, 6, 9 mean a different value for N?

I do not think so, it is clearly stated that the number 1k2, k24, has a digit that occurs twice

best.
User avatar
Basshead
Joined: 09 Jan 2020
Last visit: 07 Feb 2024
Posts: 927
Own Kudos:
Given Kudos: 432
Location: United States
Posts: 927
Kudos: 287
Kudos
Add Kudos
Bookmarks
Bookmark this Post
NoHalfMeasures
A positive integer is divisible by 3 if and only if the sum of its digits is divisible by 3. If the six-digit integer is divisible by 3, and n is of the form 1k2,k24, where k represents a digit that occurs twice, how many values could n have?

A 2
B. 3
C. 4
D. 5
E 10

We have a 6 digit integer: 1k2,k24

The 4 given digits sum to 9. This means for this number to be divisible by 3, 9 + 2k must be divisible by three.

0, 1, 2, 3, 4, 5, 6, 7, 8, 9

0, 3, 6, and 9 all work. Answer is C.
avatar
RahulSriniChelsea
Joined: 23 Apr 2020
Last visit: 20 Nov 2020
Posts: 5
Own Kudos:
Given Kudos: 11
Posts: 5
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
An easy question only made difficult in the fact that many people would have ignored the '0'. Nevertheless, practice makes perfect!
avatar
Sagart21
Joined: 25 Oct 2020
Last visit: 13 Jan 2024
Posts: 49
Own Kudos:
Given Kudos: 38
Location: India
Concentration: Strategy, General Management
Posts: 49
Kudos: 16
Kudos
Add Kudos
Bookmarks
Bookmark this Post
NoHalfMeasures
A positive integer is divisible by 3 if and only if the sum of its digits is divisible by 3. If the six-digit integer is divisible by 3, and n is of the form 1k2,k24, where k represents a digit that occurs twice, how many values could n have?

A 2
B. 3
C. 4
D. 5
E 10

1+2+2+4 = 9 which is divisible by 3
So 2k can take values which are multiples of 3
So k = 0,3,6,9
Ans: C.4
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 37,375
Own Kudos:
Posts: 37,375
Kudos: 1,010
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
   1   2 
Moderators:
Math Expert
102634 posts
PS Forum Moderator
688 posts