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31 Mar 2019, 02:08
Kudos
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
66% (01:49) correct
34%
(02:17)
wrong
based on 411
sessions
History
Date
Time
Result
Not Attempted Yet
A pump can fill a tank with water in 2 hours. Because of a leak, it took 2(1/3)
hours to fill the tank. The leak can drain all the water of the tank in ?
a. 7 hours
b. 10 hours
c. 12 hours
d. 14 hours
e. 4(2/3) hours
Posted from my mobile device
hours to fill the tank. The leak can drain all the water of the tank in ?
a. 7 hours
b. 10 hours
c. 12 hours
d. 14 hours
e. 4(2/3) hours
Posted from my mobile device
02 Apr 2019, 11:58
Kudos
Bookmarks
jackfr2
Let the draining rate be x.
It takes \(\frac{7}{3}\) hours to fill the pool with the leak. The hourly rate with the leak is \(\frac{3}{7}\).
The rate without the leak is \(\frac{1}{2}\) --> \(\frac{1}{2} - x = \frac{3}{7}\).
Solving this we get \(x = \frac{1}{14}\) so it would take 14 hours for the leak alone to empty the tank. Answer: D
02 Apr 2019, 17:58
Kudos
Bookmarks
jackfr2
without leak, pump can fill 1 tank in 2 hours,
and thus could fill 7/6 of tank in 2 1/3 hours
but, with leak, 1/6 of tank instead drains in 2 1/3 hours
6*2 1/3=14 hours to drain entire tank
D
