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31 May 2006, 04:38
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A rectangle’s perimeter is P, area is A. Is it a square?
1). p=4/3A
2). p=4RootA
1). p=4/3A
2). p=4RootA
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31 May 2006, 05:18
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A rectangle’s perimeter is P, area is A. Is it a square?
1). p=4/3A
2). p=4RootA
********************************************
I would go with B
From the question stem:
2(l+w) = P --(1)
lw = A
From Statement 1:
P = 4/3 A -- substitue this in (1)
2(l+w) = 4/3 lw
6(l+w) = 4 lw
3(l+w) = 2 lw ----Insuff.
From Statement 2:
P = 4(sqrt A)
Substitue this in (1)
l+w = 2(sqrt lw)
square both sides and get a quadratic
l^2 + -2lw +w^2 = 0
(l-w)^2 = 0
[b]l-w has to be positive --------> Can someone pls. confirm if this logic is correct?[/b]
so L = W and it is a square
1). p=4/3A
2). p=4RootA
********************************************
I would go with B
From the question stem:
2(l+w) = P --(1)
lw = A
From Statement 1:
P = 4/3 A -- substitue this in (1)
2(l+w) = 4/3 lw
6(l+w) = 4 lw
3(l+w) = 2 lw ----Insuff.
From Statement 2:
P = 4(sqrt A)
Substitue this in (1)
l+w = 2(sqrt lw)
square both sides and get a quadratic
l^2 + -2lw +w^2 = 0
(l-w)^2 = 0
[b]l-w has to be positive --------> Can someone pls. confirm if this logic is correct?[/b]
so L = W and it is a square
