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A rectangular area is covered with a rectangular rug. If the

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Joined: 11 May 2008
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A rectangular area is covered with a rectangular rug. If the [#permalink]

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New post 03 Sep 2008, 02:04
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A rectangular area is covered with a rectangular rug. If the respective sides of two rectangles are parallel to each other and have a distance of 5cm, what is the area of the large rectangle?
(1) The length of the rug is twice as long as the width of the rug.
(2) The area of the rug is 18 square centimeters.

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Re: carpet [#permalink]

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New post 03 Sep 2008, 06:36
arjtryarjtry wrote:
A rectangular area is covered with a rectangular rug. If the respective sides of two rectangles are parallel to each other and have a distance of 5cm, what is the area of the large rectangle?
(1) The length of the rug is twice as long as the width of the rug.
(2) The area of the rug is 18 square centimeters.


1) insuffcient (we need length and width of rug to find the area)

2) area is not suffcient .. (multiple solutions possible .)
insuffcient

combine
2a*a=18 --> a=3
length =6 wide=3

area of the rectangle area= (6+5)*(3+5)= 88

suffcient

C
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Last edited by x2suresh on 03 Sep 2008, 10:43, edited 1 time in total.

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New post 03 Sep 2008, 10:03
Given LA=LR+10 WA= WR+10

(1) LR = 2WR

Cant tell What is LA X WA

(2) LR X WR = 18

Cant tell What is LA X WA

Combine together we can tell what LA X WA is.

C is my answer.

Kudos [?]: 423 [0], given: 1

Re: carpet   [#permalink] 03 Sep 2008, 10:03
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A rectangular area is covered with a rectangular rug. If the

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