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# A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches

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Joined: 22 Aug 2013
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A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches  [#permalink]

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07 Mar 2018, 03:31
2
00:00

Difficulty:

75% (hard)

Question Stats:

28% (01:41) correct 72% (01:16) wrong based on 42 sessions

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A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches respectively is completely filled with water. All its water is emptied into a cylindrical tank of radius 14 inches. What is the height of the cylindrical tank?

(1) X = 11

(2) Rectangular tank has a volume of 6160 cubic inches
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Re: A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches  [#permalink]

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07 Mar 2018, 03:39
Ans : D

volume of tank = L * B * H = 35 * 16 * X
Volume of cylinder = 22/7 * 14 * 14 * h

given => 35 * 16 * X = 22/7 * 14 * 14 * h

[1] X = 11 ==> h = 10 - Sufficient

[2] = volume of tank = 6160 - so we can find out X which comes to be 11 hence plugging into equation we can get h = 10 - Sufficient
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Re: A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches  [#permalink]

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08 Mar 2018, 07:35
amanvermagmat wrote:
A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches respectively is completely filled with water. All its water is emptied into a cylindrical tank of radius 14 inches. What is the height of the cylindrical tank?

(1) X = 11

(2) Rectangular tank has a volume of 6160 cubic inches

One important thing to note is that we are not given whether the water from rectangular tank has completely filled the cylindrical tank or not. Its possible that the cylindrical tank is exactly filled completely, thus making the volume of rectangular and cylindrical tanks equal. Its also possible that water fills only 1/3rd of the cylindrical tank, thus making volume of cylindrical tank 3 times that of rectangular tank.

We can assume that volume of rectangular tank is 'n' times that of cylindrical tank. Thus 35*16*X = n * 22/7 * 14 * 14 * H
(here H is the height of cylindrical tank)

Statement 1

we get 35*16*11 = n * 22/7 * 14 * 14 * H
But without 'n', we cannot determine H. Not sufficient.

Statement 2
we get 6160 = n * 22/7 * 14 * 14 * H
Again without 'n', we cannot find H. Not sufficient.

Combining also, we dont know the value of 'n', OR we dont know the ratio of the volumes of the two tanks (Rectangular and Cylindrical). So not sufficient.

Re: A rectangular tank of dimensions 35 inches, 16 inches and 'X' inches   [#permalink] 08 Mar 2018, 07:35
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