Let’s start by finding the cost of the lobster, per bowl, in terms of the variables given (d, v, and b).

(d dollars/6 pounds) x (1 pound/v vats) x (1 vat/b bowls) = (d/6vb)

The problem states that this value, the cost of the lobster per bowl, or (d/6vb), is an integer. In other words, d is divisible by 6vb. To make d as small as possible, we need to make 6vb as small as possible. Since v and b are different prime integers, the smallest value of 6vb is 36 (using the two smallest prime integers, v = 2 and b = 3, or v = 3 and b = 2).

In order to make the cost of the lobster per bowl an integer, d must be divisible by 36. In other words, d must be a multiple of 36. What’s the smallest possible multiple of 36? The smallest multiple of 36 is 36.

The correct answer is C, 36.

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Thanks & Regards,

Anaira Mitch