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03 Jul 2019, 02:48
Kudos
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C
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A rubber ball is thrown and bounces twice before it is caught. The first time the ball bounces, it goes 5 times as high as the second time it bounces. If the second bounce goes 5 feet high, what is the combined height of the two bounces?
A. 20
B. 25
C. 30
D. 35
E. 40
A. 20
B. 25
C. 30
D. 35
E. 40
03 Jul 2019, 03:34
Kudos
Bookmarks
Bunuel
A rubber ball is thrown and bounces twice before it is caught. The first time the ball bounces, it goes 5 times as high as the second time it bounces. If the second bounce goes 5 feet high, what is the combined height of the two bounces?
A. 20
B. 25
C. 30
D. 35
E. 40
A. 20
B. 25
C. 30
D. 35
E. 40
Let the height of 2nd bounce = x = 5 (Given)
--> Height of 1st bounce = 5x = 5*5 = 25
--> Total height = 25 + 5 = 30 feet
IMO Option C
Pls Hit Kudos if you like the solution
03 Jul 2019, 10:21
Kudos
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Bunuel
A rubber ball is thrown and bounces twice before it is caught. The first time the ball bounces, it goes 5 times as high as the second time it bounces. If the second bounce goes 5 feet high, what is the combined height of the two bounces?
A. 20
B. 25
C. 30
D. 35
E. 40
A. 20
B. 25
C. 30
D. 35
E. 40
x = second bounce ; 5
first bounce = 5*x; 25
total = 25+5; 30
IMO C
