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# A salesman sold 20 cars in the month of July, and 40 cars the month of

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Math Expert
Joined: 02 Sep 2009
Posts: 64248
A salesman sold 20 cars in the month of July, and 40 cars the month of  [#permalink]

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08 Aug 2019, 00:31
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Difficulty:

5% (low)

Question Stats:

83% (00:23) correct 17% (00:30) wrong based on 59 sessions

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A salesman sold 20 cars in the month of July, and 40 cars the month of August. What is the percent increase in the number of cars the salesman sold?

A. 50%
B. 100%
C. 150%
D. 200%
E. 250%

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CrackVerbal Quant Expert
Joined: 12 Apr 2019
Posts: 590
Re: A salesman sold 20 cars in the month of July, and 40 cars the month of  [#permalink]

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09 Aug 2019, 00:50
Assuming that the question is asking about the percentage increase between July & August, we will have to put in values in the Percentage Increase equation.

Percentage Increase = $$\frac{Final Value – Initial Value}{Initial Value}$$ * 100

In this question, the initial value is the sales in July i.e. 20 cars; the final value is the sales in August i.e. 40 cars.

Therefore, percentage increase in the number of cars sold = $$\frac{40 – 20}{20}$$ * 100 = 100%.
The correct answer option is B.

In general, when the initial value becomes twice of itself, the percentage increase = 100%; if the initial value becomes thrice of itself, the percentage increase = 200%; if the intial value is x and the final value is n times of x, the percentage increase = (n-1)*100%.

The above can be used as an alternative to the general equation if you know that the final value is a direct multiple of the initial value.

Hope this helps!
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Re: A salesman sold 20 cars in the month of July, and 40 cars the month of   [#permalink] 09 Aug 2019, 00:50