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A salesman sold 20 cars in the month of July, and 40 cars the month of

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 57155
A salesman sold 20 cars in the month of July, and 40 cars the month of  [#permalink]

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New post 08 Aug 2019, 01:31
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

84% (00:23) correct 16% (00:24) wrong based on 19 sessions

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CrackVerbal Quant Expert
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Joined: 12 Apr 2019
Posts: 218
Re: A salesman sold 20 cars in the month of July, and 40 cars the month of  [#permalink]

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New post 09 Aug 2019, 01:50
Assuming that the question is asking about the percentage increase between July & August, we will have to put in values in the Percentage Increase equation.

Percentage Increase = \(\frac{Final Value – Initial Value}{Initial Value}\) * 100

In this question, the initial value is the sales in July i.e. 20 cars; the final value is the sales in August i.e. 40 cars.

Therefore, percentage increase in the number of cars sold = \(\frac{40 – 20}{20}\) * 100 = 100%.
The correct answer option is B.

In general, when the initial value becomes twice of itself, the percentage increase = 100%; if the initial value becomes thrice of itself, the percentage increase = 200%; if the intial value is x and the final value is n times of x, the percentage increase = (n-1)*100%.

The above can be used as an alternative to the general equation if you know that the final value is a direct multiple of the initial value.

Hope this helps!
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Re: A salesman sold 20 cars in the month of July, and 40 cars the month of   [#permalink] 09 Aug 2019, 01:50
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A salesman sold 20 cars in the month of July, and 40 cars the month of

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