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You're counting many possibilities several times!
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kevincan
ps_dahiya
A

To simplify,

how many 5 digits numbers can be made using 1,2,3,5,6,7 that are less than or equal to 37676. (Good approach)

My answer is 3 * 6 * 5 * 6 * 5 = 2700 ( This needs rethinking!)

So the maximum members could be 2700. None of the values in the set is less than equal to 2700. So answer should be A.


What am I doing wrong?
First digit can have 1,2,3
Second digit can have 1,2,3,5,6,7
Third digit can have 1,2,3,5,6
Fourth digit can have 1,2,3,5,6,7
Fifth digit can have 1,2,3,5,6

So I got 3*6*5*6*5 = 2700 :roll: :roll: :roll: :roll:
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If the first digit is 1, why can't the third digit be 7?
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A secret society gives each its members a five-digit code, each letter of which must be one of { 1,2,3,5,6,7 }. When a new member joins, he is issued a code that is greater that those of all existing members. A certain member has just been issued the code 37676. He knows that no members have joined after him and that everyone who has joined the society is still a member. How many elements of { 3251, 3449, 3852, 3955 } COULD be the number of members in the club?

(A) 0 (B) 1 (C) 2 (D) 3 (E) 4


B.

think of any possibility first digit will have 2 or 3 options

for those that have 3 as the option there will be atleast 1 position with even options

hence i picked the only even number.

what is the OA ?
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Hint: (number of codes possible) - (numbers above 37676)
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tough one...too tough..

anyhow my answer is B because the anwer must be multiple of 5.
if it is right, i will explain....
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ps_dahiya
A

To simplify,

how many 5 digits numbers can be made using 1,2,3,5,6,7 that are less than or equal to 37676.

My answer is 3 * 6 * 5 * 6 * 5 = 2700

So the maximum members could be 2700. None of the values in the set is less than equal to 2700. So answer should be A.

Used same approach but got a different answer
3*6*5*6*4=2240
ps_dahiya last digit can't be 6 or 7
because no members have joined after him :wink:
But the answer is still A
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Getting A but using a different approach

When first digit is 1
Number of ways the second digit can be chosen = 6
Number of ways the third digit can be chosen = 6
Number of ways the fourth digit can be chosen = 6
Number of ways the fifth digit can be chosen = 6
Hence 6^4

When the first digit is 2
Number of ways the second digit can be chosen = 6
Number of ways the third digit can be chosen = 6
Number of ways the fourth digit can be chosen = 6
Number of ways the fifth digit can be chosen = 6
Hence 6^4

When the first digit is 3
Number of ways the second digit can be chosen = 6
Number of ways the third digit can be chosen = 5
Number of ways the fourth digit can be chosen = 6
Number of ways the fifth digit can be chosen = 5
Hence 25.6^2

Total = 2.6^4 + 25.6^2
=36( 72+25) = 36*97 = 3492
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jaynayak
Getting A but using a different approach

When first digit is 1
Number of ways the second digit can be chosen = 6
Number of ways the third digit can be chosen = 6
Number of ways the fourth digit can be chosen = 6
Number of ways the fifth digit can be chosen = 6
Hence 6^4

When the first digit is 2
Number of ways the second digit can be chosen = 6
Number of ways the third digit can be chosen = 6
Number of ways the fourth digit can be chosen = 6
Number of ways the fifth digit can be chosen = 6
Hence 6^4

When the first digit is 3
Number of ways the second digit can be chosen = 6
Number of ways the third digit can be chosen = 5
Number of ways the fourth digit can be chosen = 6
Number of ways the fifth digit can be chosen = 5
Hence 25.6^2

Total = 2.6^4 + 25.6^2
=36( 72+25) = 36*97 = 3492

:oops: I knew that I am missing something.I think your approach is correct
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37676 is equal to 3852 in our decimal system:
2*6^4+5*6^3+4*6^2+5*6^1+6*6^0=1296*2+216*5+36*4+30+6=2592+1080+144+30+6=3852

Therefore 3852-1=3851 numbers can be smaller than 37676.

Hence C.
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Great work, game over! You are on the ball today. Yours is OA and OE!
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game over
37676 is equal to 3852 in our decimal system:
2*6^4+5*6^3+4*6^2+5*6^1+6*6^0=1296*2+216*5+36*4+30+6=2592+1080+144+30+6=3852

Therefore 3852-1=3851 numbers can be smaller than 37676.

Hence C.


Great answer.... got it right till 2 but forgot the fact that when the first digit is 3 and the second digit is 1....... the rest of the digits can take any of the six values....... similarily for all the places.



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