Solution
Given:• A set of n positive integers arranged in decreasing order of value
• Difference between any two consecutive numbers of the sequence = 3
To find:• The ratio of arithmetic mean of the set to the median value of the set
Approach and Working: • We know that the median of the set depends upon the number of terms in the set.
Case 1: n is odd
The terms of the set can be written as {a, a – 3, a – 3*2, a – 3*3, …. , a – 3(n-1)}
• Median = the middle term = \((n + \frac{1}{2})^{th} term = a – 3[\frac{(n + 1)}{2} – 1] = a – \frac{3(n – 1)}{2}\)
• Mean = (first term + last term)/2 = \(a + a – \frac{3(n – 1)}{2} = a – \frac{3(n – 1)}{2}\)
• Thus, median = mean
Case 2: n is even
The terms of the set can be written as {a, a – 3, a – 3*2, a – 3*3, …. , a – 3(n-1)}
• Median = average of the middle two terms = \(\frac{1}{2} * [(\frac{n}{2})^{th} term + (\frac{n}{2} + 1)^{th} term] = \frac{1}{2} * [a – 3[(\frac{n}{2} – 1] + a – 3(\frac{n}{2} + 1 – 1)] = \frac{(2a - 3n + 3)}{2} = a – \frac{3(n – 1)}{2}\)
• Mean = (first term + last term)/2 = \(a + a – \frac{3(n – 1)}{2} = a – \frac{3(n – 1)}{2}\)
• Thus, median = mean
Therefore, for any value of n, the ration of median to mean of the set is 1
Hence, the correct answer is option A.
Answer: A