Last visit was: 25 Apr 2026, 16:10 It is currently 25 Apr 2026, 16:10
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
rn1112
User avatar
Joined: 16 Jul 2022
Last visit: 21 Mar 2025
Posts: 321
Own Kudos:
227
 [3]
Given Kudos: 7
Products:
My Reviews
Posts: 321
Kudos: 227
 [3]
A ship is travelling between two port cities with a speed 01 Oct 2022, 05:58
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

75% (hard)

Question Stats:

60% (02:58) correct 40% (02:36) wrong based on 130 sessions

History

Date
Time
Result
Not Attempted Yet
A ship is travelling between two port cities with a speed such that it will reach its destination on time. After covering 25% of the distance, the ship faces an emergency and returns to its starting point with a different speed v. It then resumes travelling towards its destination without any further delay with the same speed v. By what percentage is v more than the original speed, if the ship reaches its destination in time?

A. 33.33
B. 50
C. 66.67
D. 75
E. 87.5

taken from CL GMAT
ShowHide Answer
Official Answer
C
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 25 Apr 2026
Posts: 11,229
Own Kudos:
45,020
 [2]
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
My Reviews
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,229
Kudos: 45,020
 [2]
A ship is travelling between two port cities with a speed 01 Oct 2022, 07:37
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
rn1112
A ship is travelling between two port cities with a speed such that it will reach its destination on time. After covering 25% of the distance, the ship faces an emergency and returns to its starting point with a different speed v. It then resumes travelling towards its destination without any further delay with the same speed v. By what percentage is v more than the original speed, if the ship reaches its destination in time?

A. 33.33
B. 50
C. 66.67
D. 75
E. 87.5

taken from CL GMAT
Show more


After 25% of distance or D/4 is covered, time to cover remaining 3D/4 at original speed, say x, and time to cover D + D/4 at a speed of v is same.

Thus, \(\frac{\frac{3D}{4}}{x}=\frac{\frac{5D}{4}}{v}\)

\(3v=5x………v=\frac{5x}{3}\)

Increase = \(v-x=\frac{5x}{3}-x=\frac{2x}{3}\)

Increase as a % of initial speed = \(\frac{\frac{2x}{3}}{x}*100=66.67\)


C
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,830
Own Kudos:
811,278
Given Kudos: 105,886
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,830
Kudos: 811,278
A ship is travelling between two port cities with a speed 01 Oct 2022, 08:27
Kudos
Add Kudos
Bookmarks
Bookmark this Post
rn1112
A ship is travelling between two port cities with a speed such that it will reach its destination on time. After covering 25% of the distance, the ship faces an emergency and returns to its starting point with a different speed v. It then resumes travelling towards its destination without any further delay with the same speed v. By what percentage is v more than the original speed, if the ship reaches its destination in time?

A. 33.33
B. 50
C. 66.67
D. 75
E. 87.5

taken from CL GMAT
Show more

Can you please clarify what is " L GMAT" and provide the link and/or screenshot of the question ? Thank you.
User avatar
VarshithaRS
User avatar
Joined: 05 Feb 2023
Last visit: 25 Apr 2026
Posts: 8
Own Kudos:
6
Given Kudos: 63
Posts: 8
Kudos: 6
A ship is travelling between two port cities with a speed 14 Apr 2024, 13:23
Kudos
Add Kudos
Bookmarks
Bookmark this Post
chetan2u

rn1112
A ship is travelling between two port cities with a speed such that it will reach its destination on time. After covering 25% of the distance, the ship faces an emergency and returns to its starting point with a different speed v. It then resumes travelling towards its destination without any further delay with the same speed v. By what percentage is v more than the original speed, if the ship reaches its destination in time?

A. 33.33
B. 50
C. 66.67
D. 75
E. 87.5

taken from CL GMAT
After 25% of distance or D/4 is covered, time to cover remaining 3D/4 at original speed, say x, and time to cover D + D/4 at a speed of v is same.

Thus, \(\frac{\frac{3D}{4}}{x}=\frac{\frac{5D}{4}}{v}\)

\(3v=5x………v=\frac{5x}{3}\)

Increase = \(v-x=\frac{5x}{3}-x=\frac{2x}{3}\)

Increase as a % of initial speed = \(\frac{\frac{2x}{3}}{x}*100=66.67\)


C
Show more
­May I please know, how are we considering that , 
\(\frac{\frac{3D}{4}}{x}\)

It is not mentioned in the question explicitly that, ship would have taken the same time as travelling in the velocity 'v', if the ship had started from the 25% of the distance which it had alredy covered?
@chetan2u , can you please explain me, how have you made this assumption. 

Thank you 
 ­
User avatar
zlishz
User avatar
Joined: 29 Nov 2023
Last visit: 21 Jun 2025
Posts: 53
Own Kudos:
61
 [1]
Given Kudos: 39
Location: India
GPA: 3.55
Posts: 53
Kudos: 61
 [1]
A ship is travelling between two port cities with a speed 19 Apr 2024, 04:54
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
rn1112
A ship is travelling between two port cities with a speed such that it will reach its destination on time. After covering 25% of the distance, the ship faces an emergency and returns to its starting point with a different speed v. It then resumes travelling towards its destination without any further delay with the same speed v. By what percentage is v more than the original speed, if the ship reaches its destination in time?

A. 33.33
B. 50
C. 66.67
D. 75
E. 87.5

taken from CL GMAT
Show more
­Let the total distance between the 2 ports be 4D.
Now, 25% of 4D = 1D
Let the speed of the ship at the first half of the journey be x when the ship travelled distance D and then returned because of an emergency. 
If the emergency wouldn't have occurred, the rest of the distance would have been covered at speed x only.
Thus, 3D distance at speed x. 
Time, in this case = 3D/x

Given that the speed after restarting the journey was v
Since, the ship will reach at the same time as before, it means that total distance 4D + D (while going back to the port) = 5D will be covered at speed v
Time, in this case = 5D/v

Both time are equal, so,
3D/x = 5D/v
v/x = 5/3

%= (v-x/x)*100
=(5-3/3)*100
=200/3 = 66.67%, option C 
Moderators:
Bunuel
Math Expert
109830 posts
Krunaal
Tuck School Moderator
852 posts