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Updated on: 05 Dec 2019, 11:39
Originally posted by MathRevolution on 03 Dec 2019, 01:42.
Last edited by MathRevolution on 05 Dec 2019, 11:39, edited 1 time in total.
Last edited by MathRevolution on 05 Dec 2019, 11:39, edited 1 time in total.
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[GMAT math practice question]
Some employees joined and left a company recently. The number of male employees increased by 10% and the number of female employees decreased by 10%. As a result, the number of all employees increased by 10 individuals, which is a 2% increment. How many male and female employees are there after the recent hiring?
A. \(280, 250\)
B. \(300, 200\)
C. \(330, 180\)
D. \(340, 180\)
E. \(350, 200\)
Some employees joined and left a company recently. The number of male employees increased by 10% and the number of female employees decreased by 10%. As a result, the number of all employees increased by 10 individuals, which is a 2% increment. How many male and female employees are there after the recent hiring?
A. \(280, 250\)
B. \(300, 200\)
C. \(330, 180\)
D. \(340, 180\)
E. \(350, 200\)
03 Dec 2019, 02:08
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Let the number of male employee = M, number of male employee after hiring = M+10% of M = 1.1M
Number of female employee = F, Number of Female Employee = F-10% of F = 0.9F
Net increase = 0.1M-0.1F = 10
hence, M-F = 100
Also the increase of 10 individual = 2% increase
2/100 * (M+F) = 10
M+F = 500
Solving For M & F, we get,
M = 300
F = 200
Hence after hiring, the values will be 1.1M = 330, 0.9F = 180
Answer C
Shortcut method:
The increase of 10 individual = 2% increase
2/100 * (M+F) = 10
initial (M+F) = 500 and after hiring total will be 510 (as there is a net increase of 10 employee)
Since only option C sums to 510, it is the right Answer.
Number of female employee = F, Number of Female Employee = F-10% of F = 0.9F
Net increase = 0.1M-0.1F = 10
hence, M-F = 100
Also the increase of 10 individual = 2% increase
2/100 * (M+F) = 10
M+F = 500
Solving For M & F, we get,
M = 300
F = 200
Hence after hiring, the values will be 1.1M = 330, 0.9F = 180
Answer C
Shortcut method:
The increase of 10 individual = 2% increase
2/100 * (M+F) = 10
initial (M+F) = 500 and after hiring total will be 510 (as there is a net increase of 10 employee)
Since only option C sums to 510, it is the right Answer.
MathRevolution
[GMAT math practice question]
A shop hired new employees recently. The number of male employees increased by 10% and the number of female employees decreased by 10%. As a result, the number of all employees increased by \(10\) individuals, which is a 2% increment. How many male and female employees are there after the recent hiring?
A. \(280, 250\)
B. \(300, 200\)
C. \(330, 180\)
D. \(340, 180\)
E. \(350, 200\)
A shop hired new employees recently. The number of male employees increased by 10% and the number of female employees decreased by 10%. As a result, the number of all employees increased by \(10\) individuals, which is a 2% increment. How many male and female employees are there after the recent hiring?
A. \(280, 250\)
B. \(300, 200\)
C. \(330, 180\)
D. \(340, 180\)
E. \(350, 200\)
05 Dec 2019, 01:27
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=>
Assume \(m\) and \(f\) are the numbers of male and female employees before hiring, respectively.
We have \((m + f)*(\frac{2}{100}) = 10\) or \(m + f = 500\), since the number of employees increased by \(2%\).
We have \(m(\frac{10}{100}) - f(\frac{10}{100}) = 10\) or \(m - f = 100\), since the number of male employees increased by \(10%\) and the number of female employees decreased by \(10%\).
When we add two equations, we have \((m + f) + (m - f) = 500 + 100, 2m = 600\) or \(m = 300.\)
Then \(f = 500 – m = 200.\)
There are \(1.1m = 330\) male employees and \(0.9f = 180\) female employees.
Therefore, C is the answer.
Answer: C
Assume \(m\) and \(f\) are the numbers of male and female employees before hiring, respectively.
We have \((m + f)*(\frac{2}{100}) = 10\) or \(m + f = 500\), since the number of employees increased by \(2%\).
We have \(m(\frac{10}{100}) - f(\frac{10}{100}) = 10\) or \(m - f = 100\), since the number of male employees increased by \(10%\) and the number of female employees decreased by \(10%\).
When we add two equations, we have \((m + f) + (m - f) = 500 + 100, 2m = 600\) or \(m = 300.\)
Then \(f = 500 – m = 200.\)
There are \(1.1m = 330\) male employees and \(0.9f = 180\) female employees.
Therefore, C is the answer.
Answer: C
