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12 Feb 2021, 04:30
Kudos
Bookmarks
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
42% (02:25) correct
58%
(02:06)
wrong
based on 83
sessions
History
Date
Time
Result
Not Attempted Yet
A shop sells 6 different flavors of icecream. In how many ways can a customer choose 4 ice-cream cones if they are not necessarily of different flavors?
A. 15
B. 60
C. 105
D. 125
E. 126
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
A. 15
B. 60
C. 105
D. 125
E. 126
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
13 Feb 2021, 19:44
Kudos
Bookmarks
Bunuel
See my post for this problem for reference:
https://gmatclub.com/forum/a-shop-sells ... 48794.html
The post above concludes there are 105 different cones for 2 flavors and 3 flavors. 1 flavor obviously has only 6 combinations. 4 flavors also have only 6C4 = 6C2 = 6*5/2 = 15 combinations. Thus in total 105 + 6 + 15 = 126.
Ans: E
And a note on why the answer is not 6*6*6*6, if we pick flavor A once and flavor B three times then 6^4 would include that option 4 times, with different ordering (ABBB, BABB, BBAB, BBBA) when we only want to count it once. If we pick flavor A twice then flavor B twice, then 6^4 would include that option 6 times (AABB, BBAA, ABBA, BAAB, ABAB, BABA). Thus we need to start the problem with the # of flavor perspective.
11 Apr 2024, 04:08
Kudos
Bookmarks
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