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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first

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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first [#permalink]

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New post 14 Jun 2016, 02:30
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A
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C
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E

Difficulty:

  65% (hard)

Question Stats:

56% (00:40) correct 44% (01:05) wrong based on 85 sessions

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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first day but slides down 2 feet on the second. It climbs 4 feet on the third day and slides down again 2 feet on the fourth day. If this pattern continues, how many days will it take the snail to reach the top of the wall?

A. 12
B. 16
C. 17
D. 20
E. 21

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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first [#permalink]

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New post 14 Jun 2016, 05:00
He climbs total 2 feet in 2 days. Hence, 20 days to climb 20 feet.

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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first [#permalink]

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New post Updated on: 14 Jun 2016, 22:40
2
total transaction in two days = 4-2 = 2 feet
in 16 days it will climb 16 feet
on the 17th day , the snail will climb 4 feet , thus reaching the top
therefore , total no of days required =17

Originally posted by CounterSniper on 14 Jun 2016, 05:17.
Last edited by CounterSniper on 14 Jun 2016, 22:40, edited 1 time in total.
Current Student
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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first [#permalink]

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New post 14 Jun 2016, 05:28
CounterSniper wrote:
total transaction in two days = 4-2 = 2 feet
in 16 days it will climb 16 feet
on the 17th day , the frog will climb 4 feet , thus reaching the top
therefore , total no of days required =17


Aah, you caught it buddy. One should never hurry to answer :oops:
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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first [#permalink]

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New post 14 Jun 2016, 07:37
first day 4 feet and second day it slides 2 feet,--> net effect = 2 feet in 2days
hence 16 feet in 16 days,
17th day it will reach the top

answer 17 option C
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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first [#permalink]

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New post 14 Jan 2018, 09:36
After day 1, there's a pattern on +2 feet for every odd day. So day 1 =4ft, day 3 = 6ft etc. Counting up, day 17 = 20 ft.

Answer C
Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first   [#permalink] 14 Jan 2018, 09:36
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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first

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