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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first

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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post 14 Jun 2016, 01:30
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

53% (00:46) correct 47% (01:17) wrong based on 113 sessions

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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first day but slides down 2 feet on the second. It climbs 4 feet on the third day and slides down again 2 feet on the fourth day. If this pattern continues, how many days will it take the snail to reach the top of the wall?

A. 12
B. 16
C. 17
D. 20
E. 21

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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post 14 Jun 2016, 04:00
He climbs total 2 feet in 2 days. Hence, 20 days to climb 20 feet.

IMO D
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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post Updated on: 14 Jun 2016, 21:40
2
total transaction in two days = 4-2 = 2 feet
in 16 days it will climb 16 feet
on the 17th day , the snail will climb 4 feet , thus reaching the top
therefore , total no of days required =17

Originally posted by CounterSniper on 14 Jun 2016, 04:17.
Last edited by CounterSniper on 14 Jun 2016, 21:40, edited 1 time in total.
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A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post 14 Jun 2016, 04:28
CounterSniper wrote:
total transaction in two days = 4-2 = 2 feet
in 16 days it will climb 16 feet
on the 17th day , the frog will climb 4 feet , thus reaching the top
therefore , total no of days required =17


Aah, you caught it buddy. One should never hurry to answer :oops:
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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post 14 Jun 2016, 06:37
first day 4 feet and second day it slides 2 feet,--> net effect = 2 feet in 2days
hence 16 feet in 16 days,
17th day it will reach the top

answer 17 option C
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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post 14 Jan 2018, 08:36
After day 1, there's a pattern on +2 feet for every odd day. So day 1 =4ft, day 3 = 6ft etc. Counting up, day 17 = 20 ft.

Answer C
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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first  [#permalink]

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New post 14 Dec 2018, 08:37
Speed Thrills But Kills

He climbs total 2 feet in 2 days. Hence, 20 days to climb 20 feet.

IMO D

But Wait .... on the 16th day snail reaches 16th feet and now on 17th day it reaches the top and wont be coming down to follow its pattern .

Hence Option C = 17 is the correct Choice
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Re: A snail, climbing a 20 feet high wall, climbs up 4 feet on the first &nbs [#permalink] 14 Dec 2018, 08:37
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