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Bunuel
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I'm not sure why I selected not sure when I initially answered this. Maybe I was having an off-day where I make too many basic arithmetic errors.

Anyway if they played 25 games then they won 6/10 of those which is equal to 15. Since they didn't tie any, the other 10 games must be ones which they lost... thus:
15-10=5

I can see there being a harder DS problem where they say nothing regarding ties (not sure if it has ever came up) and hopefully I'd recognize the trap if I saw it.
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Bunuel
A soccer team had no ties in the 25 games they played. If they won 60% of their games, how many more games did they win than they lost?

A. 5
B. 10
C. 15
D. 25
E. 40

Hey,

    • Most of you are calculating the actual number of wins and losses, which is not required. :)
    • If the team is winning \(60\) % of the games, then
      o They must be losing \(40\) % of the games, since there are no ties.
    • Therefore, Percentage difference = Win % - Loss% \(= 20\) %
    • Hence, number of more games won than lost = 20% of total matches\(= 20\) % of \(25 = 5\).
    • Hence, the correct answer is Option A.


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Bunuel
A soccer team had no ties in the 25 games they played. If they won 60% of their games, how many more games did they win than they lost?

A. 5
B. 10
C. 15
D. 25
E. 40

Since a team won 60% of the 25 games played, they won 0.6 x 25 = 15 games. Thus, they lost 25 - 15 = 10 games. Therefore they won 15 - 10 = 5 more games than they lost.

Answer: A
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