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A solution of acid and water is A% acid. Another solution of acid and

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A solution of acid and water is A% acid. Another solution of acid and  [#permalink]

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New post 25 Nov 2018, 21:24
1
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

33% (01:26) correct 67% (01:11) wrong based on 30 sessions

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A solution of acid and water is A% acid. Another solution of acid and water is B% acid. X litres of first solution is mixed with Y litres of second solution to form a new mixture of acid and water. What is the percentage of acid in the new mixture?

(1) Ratio of A:B = 5:4.

(2) Ratio of X:Y = 2:3.
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Re: A solution of acid and water is A% acid. Another solution of acid and  [#permalink]

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New post 28 Nov 2018, 11:46
Let the final percentage of acid in new mixture = k

A---------------B
-------k----------
k-B------------A-k

It implies that first acid solution and second acid solution should be mixed in a ratio of \(\frac{(k-B)}{(A-k)}\)

Given that X liters of first solution is mixed with Y liters of second solution

\(\frac{(k-B)}{(A-k)}\)= \(\frac{X}{Y}\)

\(Yk - YB = XA - Xk\)

\(k\)= \(\frac{(XA + YB)}{(Y + X)}\)

\(k\)= \(( (\frac{X}{Y})*A +B ) / (1 + \frac{X}{Y})\)

It is clear that we need \(\frac{X}{Y}\) , A and B to solve for k.

First Statement :

\(\frac{A}{B}\) = \(\frac{5}{4}\) -> INSUFFICIENT

Second Statement :

\(\frac{X}{Y}\) = \(\frac{2}{3}\) -> Still we need A and B. So INSUFFICIENT.

First + Second Statements:

k cannot be solved unless we know one of A and B. -> INSUFFICIENT

Therefore, Answer = E
GMAT Club Bot
Re: A solution of acid and water is A% acid. Another solution of acid and &nbs [#permalink] 28 Nov 2018, 11:46
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A solution of acid and water is A% acid. Another solution of acid and

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