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25 Nov 2018, 22:24
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E
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A solution of acid and water is A% acid. Another solution of acid and water is B% acid. X litres of first solution is mixed with Y litres of second solution to form a new mixture of acid and water. What is the percentage of acid in the new mixture?
(1) Ratio of A:B = 5:4.
(2) Ratio of X:Y = 2:3.
(1) Ratio of A:B = 5:4.
(2) Ratio of X:Y = 2:3.
28 Nov 2018, 12:46
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Let the final percentage of acid in new mixture = k
A---------------B
-------k----------
k-B------------A-k
It implies that first acid solution and second acid solution should be mixed in a ratio of \(\frac{(k-B)}{(A-k)}\)
Given that X liters of first solution is mixed with Y liters of second solution
\(\frac{(k-B)}{(A-k)}\)= \(\frac{X}{Y}\)
\(Yk - YB = XA - Xk\)
\(k\)= \(\frac{(XA + YB)}{(Y + X)}\)
\(k\)= \(( (\frac{X}{Y})*A +B ) / (1 + \frac{X}{Y})\)
It is clear that we need \(\frac{X}{Y}\) , A and B to solve for k.
First Statement :
\(\frac{A}{B}\) = \(\frac{5}{4}\) -> INSUFFICIENT
Second Statement :
\(\frac{X}{Y}\) = \(\frac{2}{3}\) -> Still we need A and B. So INSUFFICIENT.
First + Second Statements:
k cannot be solved unless we know one of A and B. -> INSUFFICIENT
Therefore, Answer = E
A---------------B
-------k----------
k-B------------A-k
It implies that first acid solution and second acid solution should be mixed in a ratio of \(\frac{(k-B)}{(A-k)}\)
Given that X liters of first solution is mixed with Y liters of second solution
\(\frac{(k-B)}{(A-k)}\)= \(\frac{X}{Y}\)
\(Yk - YB = XA - Xk\)
\(k\)= \(\frac{(XA + YB)}{(Y + X)}\)
\(k\)= \(( (\frac{X}{Y})*A +B ) / (1 + \frac{X}{Y})\)
It is clear that we need \(\frac{X}{Y}\) , A and B to solve for k.
First Statement :
\(\frac{A}{B}\) = \(\frac{5}{4}\) -> INSUFFICIENT
Second Statement :
\(\frac{X}{Y}\) = \(\frac{2}{3}\) -> Still we need A and B. So INSUFFICIENT.
First + Second Statements:
k cannot be solved unless we know one of A and B. -> INSUFFICIENT
Therefore, Answer = E
mattisweb
Joined: 30 Jul 2024
Last visit: 06 Feb 2026
Posts: 33
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Given Kudos: 14
Location: Germany
Concentration: General Management, Operations
Schools: Sloan (MIT) (D)
GMAT Focus 1: 745 Q88 V87 DI86 
GPA: 4.0
WE:Supply Chain Management (Student)
19 Aug 2025, 09:24
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Why would we need to use k? If I have a bottle of beer with 5% alcohol, then that means that 5% of the final solution is made up of alcohol, given that the other component is 0% alcohol (or acid). Therefore, the final mixture for each case is already given.
