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getzgetzu
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A square has side length 8. Above it, there is a right 05 May 2006, 23:12
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A square has side length 8. Above it, there is a right isosceles triangle (The hypotenuse is 8). What is the total area?



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Professor
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A square has side length 8. Above it, there is a right 16 May 2006, 21:33
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getzgetzu
A square has side length 8. Above it, there is a right isosceles triangle (The hypotenuse is 8). What is the total area?
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side of the triangle = 8/sqrt(2) = 4sqrt(2)
total area = (8x8) + (1/2) (4sqrt(2))(4sqrt(2)) = 80
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deowl
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A square has side length 8. Above it, there is a right 17 May 2006, 00:50
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A bit easier approach
The height of the triangle is 4, since it is equal to the half of the length of the square( assume BD is the height of the triangle ABC , so BDC is an isosceles triangle ).

So the total area is 8^2 + 16 = 80
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Natusik
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A square has side length 8. Above it, there is a right 18 May 2006, 06:01
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deowl
A bit easier approach
The height of the triangle is 4, since it is equal to the half of the length of the square( assume BD is the height of the triangle ABC , so BDC is an isosceles triangle ).

So the total area is 8^2 + 16 = 80
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Excuse me but where did you take the information that the height of the triangle is 4? There is nothing about this in the example... If it was equilaterial triangle I can solve but it's isosceles triangle...
Explain me please how you solved this example!
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A square has side length 8. Above it, there is a right 18 May 2006, 06:40
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deowl
A bit easier approach
The height of the triangle is 4, since it is equal to the half of the length of the square( assume BD is the height of the triangle ABC , so BDC is an isosceles triangle ).

So the total area is 8^2 + 16 = 80

Excuse me but where did you take the information that the height of the triangle is 4? There is nothing about this in the example... If it was equilaterial triangle I can solve but it's isosceles triangle...
Explain me please how you solved this example!
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The triangle is a right one so when you drop the height from the right
angle, it divides the triangle into two isosceles triangles.



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