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nidhihiremath
Is there any other way to solve this? How to decide which number to assume as the area.
Since the total area was of a square, the numbers could be 1^2, 2^2. 3^2,....
I took 9^2 = 81 because we need a multiple of 3... And 81 is a multiple of 3.
nidhihiremath you can try with 6^2 = 36 as well.
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Let's assume the side of the square = s

We are given that the area of A is twice that of B, hence the one side of A will be twice that of B. The other side of A and B will be equal.

Let's assume that side of A = a and the side of b = b

We know that \(\frac{a}{b}\) = \(\frac{2}{1}\)

a = 2b

a + b = s

\(\frac{Perimeter (A) }{ Perimeter (B) } \) = \(\frac{2(s+a) }{ 2(s+b) } \) = \(\frac{(s+a) }{ (s+b) } \)

At this stage, we can assume the value of s in such a manner that its a multiple of 3.

Let's assume s = 6

a + b = 6

2b + b = 6

b = 2

a = 4

Let's substitute this information into the ratio -

\(\frac{Perimeter (A) }{ Perimeter (B) } \) = \(\frac{(s+a) }{ (s+b) } \)

= \(\frac{(6+4) }{ (6+2) } \)

= \(\frac{10 }{ 8 } \)

= \(\frac{5 }{ 4} \)

Option A
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nidhihiremath
Is there any other way to solve this? How to decide which number to assume as the area.


A pretty fast and straightforward way of getting to the solution is taking the unit square as we can just cut two opposing side lengths in the ratio to the areas given. I can't yet upload images so here's a description.

So we cut it into:
- a rectangle with side lengths \(\frac{1}{3}\) and \(1\), being the smaller rectangle (Rectangle \(B\))
- the other one will then be a rectangle with side lengths \(\frac{2}{3}\) and \(1\) (Rectangle \(A\) - with twice the area of rectangle \(B\))

Then we just add up the side lengths to get the perimeter of each rectangle:
Perimeter\(A = \frac{2}{3} + \frac{2}{3} + 1 + 1 = \frac{10}{3}\)
Perimeter\(B = \frac{1}{3} + \frac{1}{3} + 1 + 1 = \frac{8}{3}\)

And get the ratio:
\(\frac{Perimeter A}{Perimeter B}\) = \(\frac{10 * 3}{8 * 3}\) = \(\frac{10}{8}\) = \(\frac{5}{4}\)
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The figure below represents the square.

The x's and the y's are small squares of equal sizes. The x's together are the bigger rectangle and the y's together are the smaller rectangle.

x x x
x x x
y y y

Now just count.
Perimeter of the bigger square = 10
Perimeter of the smaller square = 8

Ratio = 10/8 = 5/4 = A

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