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27 Mar 2006, 18:31
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1. A stick is broken into 2 pieces. One of the pieces is further broken into two pieces.
What is the probability that the (three) pieces so obtained form the sides of a triangle ?
What is the probability that the (three) pieces so obtained form the sides of a triangle ?
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27 Mar 2006, 19:13
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One piece is broken into 2 pieces, lets call them x & y.
it can be done in 3 possible ways which is
x = y ; x > y ; x 3rd side and difference of 2 sides y or y > x can produce the desired results. Therefore Prob of the desired event - 2/3
To form a triangle the longer piece should be further broken in to 2
Assuming x > y,
If x is further broken into x1 & x2 then the possible events can be
x2 - x1 = y ; x2 - x1 > y; x2 - x1 < y. what we need is x2 - x1 < y. Therefore 1/3.
So final answer is 2/3 * 1/3 = 2/9.
A Sincere try. Hope I got it right
it can be done in 3 possible ways which is
x = y ; x > y ; x 3rd side and difference of 2 sides y or y > x can produce the desired results. Therefore Prob of the desired event - 2/3
To form a triangle the longer piece should be further broken in to 2
Assuming x > y,
If x is further broken into x1 & x2 then the possible events can be
x2 - x1 = y ; x2 - x1 > y; x2 - x1 < y. what we need is x2 - x1 < y. Therefore 1/3.
So final answer is 2/3 * 1/3 = 2/9.
A Sincere try. Hope I got it right
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
