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08 Mar 2026, 23:56
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A
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Difficulty:
65%
(hard)
Question Stats:
63% (03:03) correct
37%
(03:26)
wrong
based on 41
sessions
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A store sells two kinds of whole chickens: regular and free-range. The price of a free-range chicken is 40 percent higher than the price of a regular chicken. Last year, free-range chickens accounted for r percent of the store’s revenue from the sale of whole chickens (0 < r < 100). What percent of the chickens sold by the store last year were free-range?
A. 100r / (140 − 0.4r) percent
B. 100r / (140 − 0.5r) percent
C. 100r / (100 − 0.4r) percent
D. 100r / (140 + 0.4r) percent
E. 100r / (100 + 0.4r) percent
A. 100r / (140 − 0.4r) percent
B. 100r / (140 − 0.5r) percent
C. 100r / (100 − 0.4r) percent
D. 100r / (140 + 0.4r) percent
E. 100r / (100 + 0.4r) percent
09 Mar 2026, 00:34
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kevincan
Let the quantity of regular chicken, and free range chicken be a,b respectively.
The price of the Free range and Regular Chicken = 7:5
Given that : revenue of free range chicken to Total is r%
So, 7b / (7b+5a) = (r/100)
We need to find : What percent of the chickens sold by the store last year were free-range?
b/(b+a) = ?
From this equation, 7b / (7b+5a) = (r/100)
(100/r) = (7b+5a)/7b
= 1 + (5a/7b)
(5a/7b) = (100/r) - 1
(5a/7b) = (100 - r)/r
(a/b) = ( 700 - 7r)/ 5r
adding 1 to both sides we get
(a+b)/b = [ (700-7r)+5r ]/ 5r
(a+b)/b = (700-2r)/5r
b/(a+b) = 5r / (700 - 2r)
dividing by 5, we get
b/(a+b) = r / (140 - 0.4r)
so,
b/(a+b) *100 =
100r / (140 - 0.4r)
Option A
