Bunuel
A straight pipe 1 yard in length was marked off in fourths and also in thirds. If the pipe was then cut into separate pieces, at each of these markings, which of the following gives all the different lengths of the pieces, in fractions of a yard?
I. \(\frac{1}{6}\)
II. \(\frac{1}{4}\)
III. \(\frac{1}{12}\)
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
To create 1/4 markings we need 3 slices, to create 1/3 markings we need 2 slices.
We can split the pipe in half first. Then from left to right, we will have the first 1/4 marking, the first 1/3 marking, then the second 1/4 marking (one-half marking). The other half is symmetrical so we only need to observe the first half.
So we will have a 1/4 pipe, then a \(\frac{1}{3} - \frac{1}{4} = \frac{1}{12}\) pipe, then \(\frac{1}{2} - \frac{1}{3} = \frac{1}{6}\) pipe before we reach the halfway point.
Ans: E