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A student approximates that he needs 1 gram of sugar for every 0.8

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A student approximates that he needs 1 gram of sugar for every 0.8  [#permalink]

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New post 27 Mar 2019, 17:06
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D
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A student approximates that he needs 1 gram of sugar for every 0.8 liters of solution. Which of the following is the best approximation of the number of grams he would need for 3 liters of solution?

A) \(\frac{4}{5}\)

B) \(\frac{5}{12}\)

C) \(\frac{12}{5}\)

D) \(\frac{15}{4}\)

E) \(\frac{19}{5}\)
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Re: A student approximates that he needs 1 gram of sugar for every 0.8  [#permalink]

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New post 27 Mar 2019, 18:26
energetics wrote:
A student approximates that he needs 1 gram of sugar for every 0.8 liters of solution. Which of the following is the best approximation of the number of grams he would need for 3 liters of solution?

A) \(\frac{4}{5}\)

B) \(\frac{5}{12}\)

C) \(\frac{12}{5}\)

D) \(\frac{15}{4}\)

E) \(\frac{19}{5}\)


I like solving this kind of thing by 'scaling up' the ratio, to avoid doing a ton of math.

1 gram in 0.8 liters
*10
10 grams in 8 liters
/8
10/8 grams in 1 liter
*3
30/8 grams in 3 liters

30/8 = 15/4, or answer (D).
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Re: A student approximates that he needs 1 gram of sugar for every 0.8  [#permalink]

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New post 02 Apr 2019, 19:18
energetics wrote:
A student approximates that he needs 1 gram of sugar for every 0.8 liters of solution. Which of the following is the best approximation of the number of grams he would need for 3 liters of solution?

A) \(\frac{4}{5}\)

B) \(\frac{5}{12}\)

C) \(\frac{12}{5}\)

D) \(\frac{15}{4}\)

E) \(\frac{19}{5}\)


We can use the following proportion:

1/(0.8) = n/3

3 = 0.8n

30 = 8n

n = 30/8 = 15/4

Answer: D
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Re: A student approximates that he needs 1 gram of sugar for every 0.8   [#permalink] 02 Apr 2019, 19:18
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