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Bunuel
A student finds the average of 10 positive integers. Each integer contains two digits. By mistake, the boy interchanges the digits of one number say ba for ab. Due to this, the average becomes 1.8 less than the previous one. What was the difference of the two digits a and b?

A. 8
B. 6
C. 4
D. 2
E. 1

The correct number ab can be written as 10a+b

The wrongly taken number be ba which can be written as 10b+a

the average of 10 numbers is brought down by 1.8

so the difference of these two numbers (10a +b) - (10b+a) = 18

9a - 9b = 18

a - b = 2
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Bunuel
A student finds the average of 10 positive integers. Each integer contains two digits. By mistake, the boy interchanges the digits of one number say ba for ab. Due to this, the average becomes 1.8 less than the previous one. What was the difference of the two digits a and b?

A. 8
B. 6
C. 4
D. 2
E. 1


Just as the number 36 can be expressed as 3 x 10 + 6, we can express the two-digit number ab as 10a + b. Similarly, the number ba can be expressed as 10b + a.

With the above in mind, we can let the sum of the other 9 (correct) numbers be x and create the equation:

(x + 10a + b)/10 = (x + 10b + a)/10 - 1.8

Multiplying both sides by 10, we have:

x + 10a + b = x + 10b + a - 18

10a + b = 10b + a - 18

9a - 9b = -18

9(a - b) = -18

a - b = -2

b - a = 2

So the difference between the two digits is 2.

Answer: D
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