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A student’s average test score in algebra is 88 after eight tests have 15 Oct 2020, 08:45
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D
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15% (low)

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84% (01:52) correct 16% (01:56) wrong based on 63 sessions

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A student’s average test score in algebra is 88 after eight tests have been taken. When the teacher drops the student’s two lowest test scores, the student’s average score increases to 92. What is the average score of the two tests that were dropped?

A. 72

B. 74

C. 75

D. 76

E. 78
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D
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A student’s average test score in algebra is 88 after eight tests have 15 Oct 2020, 09:02
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Explanation:

total score for 8 test = 88*8 = 704
total score for 6 test = 92*6 = 552
Difference = 704-552 = 152 i.e. sum of 2 lowest score
Average of 2 lowest score = 152/2 = 76

IMO-D
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A student’s average test score in algebra is 88 after eight tests have 15 Oct 2020, 11:45
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Solution:
The total score of the 8 tests are: 88*8= 704;
The total score of the 6 tests after the lowest scores are dropped: 92*6= 552;
The total of the two lowest scores= 704-552= 152;
Average of the two lowest scores= 152/2= 76;

Therefore, the answer is D.
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A student’s average test score in algebra is 88 after eight tests have 15 Oct 2020, 13:56
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Bunuel
A student’s average test score in algebra is 88 after eight tests have been taken. When the teacher drops the student’s two lowest test scores, the student’s average score increases to 92. What is the average score of the two tests that were dropped?

A. 72

B. 74

C. 75

D. 76

E. 78
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Let the sum of the score of top 6 tests be "X".
Let the scores of lowest 2 tests be "Y" and "Z".

=> X+Y+Z = 88*8 = 704
=> X = 92*6 = 552

=> Y+Z = 704-552 = 152
=> Average score of the two tests that were dropped = 152/2 = 76

IMO is D.

Thanks :)
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A student’s average test score in algebra is 88 after eight tests have 22 Oct 2020, 10:43
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Bunuel
A student’s average test score in algebra is 88 after eight tests have been taken. When the teacher drops the student’s two lowest test scores, the student’s average score increases to 92. What is the average score of the two tests that were dropped?

A. 72

B. 74

C. 75

D. 76

E. 78
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Solution:

We can let x = the average of his two lowest test scores and create the equation:

2x + 6(92) = 8(88)

2x + 552 = 704

2x = 152

x = 76

Alternate Solution:

Since average = sum/number, we see that average x number = sum. Thus, the sum of all scores before the two tests were dropped was 88 x 8 = 704.

After the two lowest test scores were dropped, the average of the remaining 6 scores was 92. Thus, we see that the sum of these 6 scores was 92 x 6 = 552.

The difference of the two sums is 704 - 552 = 152, and this is the sum of the two lowest scores. Thus, the average of these two scores is 152 / 2 = 76.

Answer: D
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A student’s average test score in algebra is 88 after eight tests have 27 Oct 2020, 07:00
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An alternate approach without any calculation

Mean is the measure of each element when their sum is evenly distributed across all of them.

Assume, there are 8 tests and the student has scored 88 in each of them. When the 2 tests with the least scores are removed, the mean of the remaining 6 becomes 92. This implies that the total increase in each of the remaining 6 tests ie, 6*4=24 were the excess in the 2 tests so as to compensate for their deficiency and bring the mean to 88. So, the total of the actual scores the student has scored in those 2 tests will be 24 less than 88*2 or the mean score in the 2 test will be 12 less than 88.

76, Option D
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