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A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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10 Nov 2010, 10:14

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Question Stats:

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A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive?

Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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10 Nov 2010, 11:36

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mrinal2100 wrote:

A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive? A) 20 B) 22 C) 24 D) 26 E) 52

Start with Chloe. Chloe got $32 which was 2/3rd of what was remaining after Bob received $4. So 1/3 that Bob received must have been $16. This was remaining when Bob had already been given $4 In all, Bob received $16 + $4 = $20
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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11 Dec 2010, 02:27

Another way of solving this problem is by plugging in numbers : Take total sum =108 Then the share of ann=4+104/2=56 104-52 =52 remains The for Bob 4+48/3=20 For charlote $32 remains

Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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11 Dec 2010, 04:03

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rite2deepti wrote:

Another way of solving this problem is by plugging in numbers : Take total sum =108 Then the share of ann=4+104/2=56 104-52 =52 remains The for Bob 4+48/3=20 For charlote $32 remains

Yes, plugging in numbers is a great strategy whenever applicable. The only small issue with it is that sometimes you need to go through the process multiple times before you get the answer. The more calculations you do, more time is lost and more are the chances of you making a calculation error. Though you will take a call according to your comfort with each question type, but if the question is straight forward and you know how to get the answer, my advice would be to solve it rather than going backwards.
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Re: A sum of money was distributed among Lyle, Bob and Chloe...
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20 Jul 2016, 05:21

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DensetsuNo wrote:

A sum of money was distributed among Lyle, Bob and Chloe. First, Lyle received 4 dollars plus one-half of what remained. Next, Bob received 4 dollars plus one-third of what remained. Finally, Chloe received the remaining $32. How many dollars did Bob receive?

A) 10 B) 20 C) 26 D) 40 E) 52

Kudos if you like!

Notice that we need not consider Ann's portion in the solution. We can just let K = the money REMAINING after Ann has received her portion and go from there. Our equation will use the fact that, once we remove Bob's portion, we have $32 for Chloe. So, we get K - Bob's $ = 32

Bob received 4 dollars plus one-third of what remained Once Bob receives $4, the amount remaining is K-4 dollars. So, Bob gets a 1/3 of that as well. 1/3 of K-4 is (K-4)/3 So ALTOGETHER, Bob receives 4 + (K-4)/3

So, our equation becomes: K - [4 + (K-4)/3 ] = 32 Simplify to get: K - 4 - (K-4)/3 = 32 Multiply both sides by 3 to get: 3K - 12 - K + 4 = 96 Simplify: 2K - 8 = 96 Solve: K = 52

Plug this K-value into K - Bob's $ = 32 to get: 52 - Bob's $ = 32 So, Bob's $ = 20

Re: A sum of money was distributed among Lyle, Bob and Chloe...
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20 Jul 2016, 05:26

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DensetsuNo wrote:

A sum of money was distributed among Lyle, Bob and Chloe. First, Lyle received 4 dollars plus one-half of what remained. Next, Bob received 4 dollars plus one-third of what remained. Finally, Chloe received the remaining $32. How many dollars did Bob receive?

A) 10 B) 20 C) 26 D) 40 E) 52

Another approach:

This time, let K = the money REMAINING after Ann has received her portion AND after Bob has taken $4. At this point, Bob receives 1/3 of K, and Chloe gets the rest. This means that Chloe receives 2/3 of K

Since Chloe receives $32, we can say that: (2/3)K = 32 Multiply both sides by 3/2 to get: K = 48

Since Bob receives 1/3 of K plus $4, we can see that the amount Bob gets = (1/3)(48) + 4 = $20

Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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20 Jul 2016, 21:46

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mrinal2100 wrote:

A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive?

A) 20 B) 22 C) 24 D) 26 E) 52

Let money remaining after Ann got her share and after Bob took $4 be x. This is also equal to 32 +x/3. So, 32 + x/3 = x x=48 . So Bob got x/3 + 4 = 20
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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19 Jul 2017, 10:10

VeritasPrepKarishma wrote:

mrinal2100 wrote:

A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive? A) 20 B) 22 C) 24 D) 26 E) 52

Start with Chloe. Chloe got $32 which was 2/3rd of what was remaining after Bob received $4. So 1/3 that Bob received must have been $16. This was remaining when Bob had already been given $4 In all, Bob received $16 + $4 = $20

Can you explain how did you get 2/3rd of what was remaining was 32? As we keep on adding 4 to fractions of what was remaining in case of A and B.

Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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20 Jul 2017, 01:55

SOUMYAJIT_ wrote:

VeritasPrepKarishma wrote:

mrinal2100 wrote:

A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive? A) 20 B) 22 C) 24 D) 26 E) 52

Start with Chloe. Chloe got $32 which was 2/3rd of what was remaining after Bob received $4. So 1/3 that Bob received must have been $16. This was remaining when Bob had already been given $4 In all, Bob received $16 + $4 = $20

Can you explain how did you get 2/3rd of what was remaining was 32? As we keep on adding 4 to fractions of what was remaining in case of A and B.

Question tells us: "Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32."

Bob received $4 and a third a what remained. So 2/3rd was finally what was left for Chloe. That 2/3rd was $32.
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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20 Jul 2017, 03:09

[/quote]

Can you explain how did you get 2/3rd of what was remaining was 32? As we keep on adding 4 to fractions of what was remaining in case of A and B.[/quote]

Question tells us: "Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32."

Bob received $4 and a third a what remained. So 2/3rd was finally what was left for Chloe. That 2/3rd was $32.[/quote]

Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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25 Jul 2017, 10:50

mrinal2100 wrote:

A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives $4 plus one-half of what remains. Next, Bob receives $4 plus one-third of what remains. Finally, Chloe receives the remaining $32. How much money did Bob receive?

A) 20 B) 22 C) 24 D) 26 E) 52

We can let the total amount of money = n.

Thus, Ann receives:

4 + ½(n - 4)

4 + ½n - 2

½n + 2

Bob receives:

4 + ⅓[n - 4 - Ann]

4 + ⅓[n - 4 - (½n + 2)]

4 + ⅓[n - 4 - ½n - 2]

4 + ⅓[½n - 6] = 4 + ⅙n - 2

⅙n + 2

Since we are given that Chloe receives the remaining $32, we can create the following equation, which combines Ann’s money, Bob’s money, and Chloe’s money:

½n + 2 + ⅙n + 2 + 32 = n

Multiplying both sides by 6, we have:

3n + 12 + n + 12 + 192 = 6n

4n + 216 = 6n

2n = 216

n = 108

Thus, Bob receives:

⅙(108) + 2 = 18 + 2 = $20

Answer: A
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r
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