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Manager  Joined: 29 Sep 2008
Posts: 85
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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Difficulty:   75% (hard)

Question Stats: 58% (02:28) correct 42% (03:05) wrong based on 126 sessions

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A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?

A) 20
B) 22
C) 24
D) 26
E) 52
Veritas Prep GMAT Instructor V
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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mrinal2100 wrote:
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?
A) 20
B) 22
C) 24
D) 26
E) 52

Chloe got \$32 which was 2/3rd of what was remaining after Bob received \$4.
So 1/3 that Bob received must have been \$16.
This was remaining when Bob had already been given \$4
In all, Bob received \$16 + \$4 = \$20
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Intern  Joined: 07 Aug 2010
Posts: 1
Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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3
Total = s
Ann = 4+(1/2)(s-4) = (1/2)s+2
Bob = 4+(1/3)(s-4-(Ann)) = 4+(1/3)(s-4-((1/2)s+2)) = (1/6)s+2
Chlore = 32
A+B+C = s => s = 108
Bob = 20
Ans: A

OA pls.
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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Another way of solving this problem is by plugging in numbers :
Take total sum =108
Then the share of ann=4+104/2=56
104-52 =52 remains
The for Bob 4+48/3=20
For charlote \$32 remains Veritas Prep GMAT Instructor V
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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rite2deepti wrote:
Another way of solving this problem is by plugging in numbers :
Take total sum =108
Then the share of ann=4+104/2=56
104-52 =52 remains
The for Bob 4+48/3=20
For charlote \$32 remains Yes, plugging in numbers is a great strategy whenever applicable. The only small issue with it is that sometimes you need to go through the process multiple times before you get the answer. The more calculations you do, more time is lost and more are the chances of you making a calculation error. Though you will take a call according to your comfort with each question type, but if the question is straight forward and you know how to get the answer, my advice would be to solve it rather than going backwards.
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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Thanks for the explanation Karishma
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Re: A sum of money was distributed among Lyle, Bob and Chloe...  [#permalink]

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DensetsuNo wrote:
A sum of money was distributed among Lyle, Bob and Chloe. First, Lyle received 4 dollars plus one-half of what remained. Next, Bob received 4 dollars plus one-third of what remained. Finally, Chloe received the remaining \$32. How many dollars did Bob receive?

A) 10
B) 20
C) 26
D) 40
E) 52

Kudos if you like!

Notice that we need not consider Ann's portion in the solution. We can just let K = the money REMAINING after Ann has received her portion and go from there.
Our equation will use the fact that, once we remove Bob's portion, we have \$32 for Chloe.
So, we get K - Bob's \$ = 32

Bob received 4 dollars plus one-third of what remained
Once Bob receives \$4, the amount remaining is K-4 dollars. So, Bob gets a 1/3 of that as well.
1/3 of K-4 is (K-4)/3
So ALTOGETHER, Bob receives 4 + (K-4)/3

So, our equation becomes: K - [4 + (K-4)/3 ] = 32
Simplify to get: K - 4 - (K-4)/3 = 32
Multiply both sides by 3 to get: 3K - 12 - K + 4 = 96
Simplify: 2K - 8 = 96
Solve: K = 52

Plug this K-value into K - Bob's \$ = 32 to get: 52 - Bob's \$ = 32
So, Bob's \$ = 20

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Re: A sum of money was distributed among Lyle, Bob and Chloe...  [#permalink]

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Top Contributor
DensetsuNo wrote:
A sum of money was distributed among Lyle, Bob and Chloe. First, Lyle received 4 dollars plus one-half of what remained. Next, Bob received 4 dollars plus one-third of what remained. Finally, Chloe received the remaining \$32. How many dollars did Bob receive?

A) 10
B) 20
C) 26
D) 40
E) 52

Another approach:

This time, let K = the money REMAINING after Ann has received her portion AND after Bob has taken \$4.
At this point, Bob receives 1/3 of K, and Chloe gets the rest.
This means that Chloe receives 2/3 of K

Since Chloe receives \$32, we can say that: (2/3)K = 32
Multiply both sides by 3/2 to get: K = 48

Since Bob receives 1/3 of K plus \$4, we can see that the amount Bob gets = (1/3)(48) + 4 = \$20

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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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mrinal2100 wrote:
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?

A) 20
B) 22
C) 24
D) 26
E) 52

Let money remaining after Ann got her share and after Bob took \$4 be x.
This is also equal to 32 +x/3.
So, 32 + x/3 = x
x=48 . So Bob got x/3 + 4 = 20
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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VeritasPrepKarishma wrote:
mrinal2100 wrote:
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?
A) 20
B) 22
C) 24
D) 26
E) 52

Chloe got \$32 which was 2/3rd of what was remaining after Bob received \$4.
So 1/3 that Bob received must have been \$16.
This was remaining when Bob had already been given \$4
In all, Bob received \$16 + \$4 = \$20

Can you explain how did you get 2/3rd of what was remaining was 32? As we keep on adding 4 to fractions of what was remaining in case of A and B.
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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SOUMYAJIT_ wrote:
VeritasPrepKarishma wrote:
mrinal2100 wrote:
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?
A) 20
B) 22
C) 24
D) 26
E) 52

Chloe got \$32 which was 2/3rd of what was remaining after Bob received \$4.
So 1/3 that Bob received must have been \$16.
This was remaining when Bob had already been given \$4
In all, Bob received \$16 + \$4 = \$20

Can you explain how did you get 2/3rd of what was remaining was 32? As we keep on adding 4 to fractions of what was remaining in case of A and B.

Question tells us: "Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32."

Bob received \$4 and a third a what remained. So 2/3rd was finally what was left for Chloe. That 2/3rd was \$32.
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Joined: 08 Mar 2016
Posts: 28
Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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[/quote]

Can you explain how did you get 2/3rd of what was remaining was 32? As we keep on adding 4 to fractions of what was remaining in case of A and B.[/quote]

Question tells us: "Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32."

Bob received \$4 and a third a what remained. So 2/3rd was finally what was left for Chloe. That 2/3rd was \$32.[/quote]

Yup!! Sorry.. Stupid question!!
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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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mrinal2100 wrote:
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?

A) 20
B) 22
C) 24
D) 26
E) 52

We can let the total amount of money = n.

4 + ½(n - 4)

4 + ½n - 2

½n + 2

4 + ⅓[n - 4 - Ann]

4 + ⅓[n - 4 - (½n + 2)]

4 + ⅓[n - 4 - ½n - 2]

4 + ⅓[½n - 6] = 4 + ⅙n - 2

⅙n + 2

Since we are given that Chloe receives the remaining \$32, we can create the following equation, which combines Ann’s money, Bob’s money, and Chloe’s money:

½n + 2 + ⅙n + 2 + 32 = n

Multiplying both sides by 6, we have:

3n + 12 + n + 12 + 192 = 6n

4n + 216 = 6n

2n = 216

n = 108

⅙(108) + 2 = 18 + 2 = \$20

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Re: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann r  [#permalink]

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mrinal2100 wrote:
A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32. How much money did Bob receive?

A) 20
B) 22
C) 24
D) 26
E) 52

Given: A sum of money is to be divided among Ann, Bob and Chloe. First, Ann receives \$4 plus one-half of what remains. Next, Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32.

Asked: How much money did Bob receive?

Bob receives \$4 plus one-third of what remains. Finally, Chloe receives the remaining \$32.
Chloe receives 2/3rd of what remains = \$32
1/3 rd of what remains = \$16
Bob receives = 16+4 =\$20

IMO A
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