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A team scored an average (arithmetic mean) of a points for the first x

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A team scored an average (arithmetic mean) of a points for the first x  [#permalink]

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New post 22 Aug 2018, 01:09
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A team scored an average (arithmetic mean) of a points for the first x games of the season, and it scored an average of b points for all y games of the season, where a, b, x, and y are integers and y > x > 0. What was the team's average score for the games played after the first x games?

A. (by-ax)/(y-x)

B. (ax+by)/(x+y)

C. (ax+by)/(2y)

D. (by-ax)/(x+y)

E. y/b - x/a

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Re: A team scored an average (arithmetic mean) of a points for the first x  [#permalink]

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New post 22 Aug 2018, 01:14
The number of games played after the x games is y-x.

Only option A has the denominator as y-x.

A is the answer.

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Re: A team scored an average (arithmetic mean) of a points for the first x  [#permalink]

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New post 22 Aug 2018, 01:20
Bunuel wrote:
A team scored an average (arithmetic mean) of a points for the first x games of the season, and it scored an average of b points for all y games of the season, where a, b, x, and y are integers and y > x > 0. What was the team's average score for the games played after the first x games?

A. (by-ax)/(y-x)

B. (ax+by)/(x+y)

C. (ax+by)/(2y)

D. (by-ax)/(x+y)

E. y/b - x/a


Sum of points scored in the 1st 'x' games=Avg of a games * 'a' no of games=ay
Total sum of points=Avg of y games * y no of games=by
So, sum of points scored after x games = by-ax
# of games played after x games = y-x
Average = Sum of points scored after x games/Total no of games after x games=\(\frac{(by-ax)}{(y-x)}\)

Ans. (A)
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Re: A team scored an average (arithmetic mean) of a points for the first x  [#permalink]

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New post 22 Aug 2018, 01:24

Solution



Given:
    • A team scored an average (arithmetic mean) of ‘a’ points for the first x games of the season.
    • It scored an average of ‘b’ points for all y games of the season.
    • Also, a, b, x, and y are integers and y > x > 0.

To find:
    • The team's average score for the games played after the first x games.

Approach and Working:
Average score in the first x games is ‘a’.
    • Hence, total score in the first x games = ax

Average score in all y games is ‘b’.
    • Hence, total score in all y games = by

    • Therefore, total score in the last (y – x) games = by – ax
    • Hence, average in the last (y – x) games = (by – ax)/(y – x)

Hence, the correct answer is option A.

Answer: A

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Re: A team scored an average (arithmetic mean) of a points for the first x  [#permalink]

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New post 23 Aug 2018, 22:24
EgmatQuantExpert wrote:

Solution



Given:
    • A team scored an average (arithmetic mean) of ‘a’ points for the first x games of the season.
    • It scored an average of ‘b’ points for all y games of the season.
    • Also, a, b, x, and y are integers and y > x > 0.

To find:
    • The team's average score for the games played after the first x games.

Approach and Working:
Average score in the first x games is ‘a’.
    • Hence, total score in the first x games = ax

Average score in all y games is ‘b’.
    • Hence, total score in all y games = by

    • Therefore, total score in the last (y – x) games = by – ax
    • Hence, average in the last (y – x) games = (by – ax)/(y – x)

Hence, the correct answer is option A.

Answer: A

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Hi EgmatQuantExpert,

OA:E, Could you please explain?

Thanking you in advance.
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PKN

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Re: A team scored an average (arithmetic mean) of a points for the first x  [#permalink]

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New post 23 Aug 2018, 22:54
Bunuel wrote:
A team scored an average (arithmetic mean) of a points for the first x games of the season, and it scored an average of b points for all y games of the season, where a, b, x, and y are integers and y > x > 0. What was the team's average score for the games played after the first x games?

A. (by-ax)/(y-x)

B. (ax+by)/(x+y)

C. (ax+by)/(2y)

D. (by-ax)/(x+y)

E. y/b - x/a


It's a weighted average problem. Use Avg = (C1*w1 + C2*w2)/(w1 + w2)
Let U be the average of (y - x) games.

b = [ax + U(y - x)]/y

U = (by - ax)/(y - x)

Answer (A)
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Re: A team scored an average (arithmetic mean) of a points for the first x &nbs [#permalink] 23 Aug 2018, 22:54
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