Bunuel wrote:

A team scored an average (arithmetic mean) of a points for the first x games of the season, and it scored an average of b points for all y games of the season, where a, b, x, and y are integers and y > x > 0. What was the team's average score for the games played after the first x games?

A. (by-ax)/(y-x)

B. (ax+by)/(x+y)

C. (ax+by)/(2y)

D. (by-ax)/(x+y)

E. y/b - x/a

Sum of points scored in the 1st 'x' games=Avg of a games * 'a' no of games=ay

Total sum of points=Avg of y games * y no of games=by

So, sum of points scored after x games = by-ax

# of games played after x games = y-x

Average = Sum of points scored after x games/Total no of games after x games=\(\frac{(by-ax)}{(y-x)}\)

Ans. (A)

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Regards,

PKN

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