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# A theater with 600 seats sells tickets at $1.20,$1.80, or $2.40 per s SORT BY: Tags: Show Tags Hide Tags Math Expert Joined: 02 Sep 2009 Posts: 95507 Own Kudos [?]: 658649 [25] Given Kudos: 87257 Most Helpful Reply GMAT Club Legend Joined: 12 Sep 2015 Posts: 6803 Own Kudos [?]: 31323 [10] Given Kudos: 799 Location: Canada General Discussion IESE School Moderator Joined: 11 Feb 2019 Posts: 270 Own Kudos [?]: 177 [1] Given Kudos: 53 Director Joined: 21 Feb 2017 Posts: 507 Own Kudos [?]: 1114 [0] Given Kudos: 1091 Location: India GMAT 1: 700 Q47 V39 A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]
VeritasKarishma i tried to do this with weights
avg cost per ticket after accounting for 200 tickets sold @ 1.80 is 660/400 = 1.4
1.4-1.2 = 0.2
2.4-1.4= 1
ratio of tickets sold 1.20 and 2.40 = 2/10
tickets sold at 2.40 = 2/12*660 =110

could you help me with where i am faltering?

Originally posted by Kritisood on 04 Jun 2020, 03:19.
Last edited by Kritisood on 23 Jul 2020, 08:41, edited 1 time in total.
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A theater with 600 seats sells tickets at $1.20,$1.80, or $2.40 per s [#permalink] 1 Kudos 1 Bookmarks Bunuel A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per seat. On Wednesday evening, 1/3 of the tickets sold were at $1.80 per seat and the total receipts from the sale of 600 tickets was$1,020. How many of the tickets sold were at $2.40 per seat? A. 150 B. 160 C. 200 D. 250 E. 300 PS20373 $$200*1.80 + 1.20*a + 2.40*b = 1020$$ Or, 1.20a + 2.40b = 660 Or, $$a + 2b = 550$$ Further we know , $$a + b = 400$$ Now substitute values $$400 - b + 2b = 550$$ So, $$b = 150$$ , thus $$a = 250$$ Thus, Answer must be (A) 150 Target Test Prep Representative Joined: 14 Oct 2015 Status:Founder & CEO Affiliations: Target Test Prep Posts: 19460 Own Kudos [?]: 23246 [0] Given Kudos: 286 Location: United States (CA) Re: A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]
Bunuel
A theater with 600 seats sells tickets at $1.20,$1.80, or $2.40 per seat. On Wednesday evening, 1/3 of the tickets sold were at$1.80 per seat and the total receipts from the sale of 600 tickets was $1,020. How many of the tickets sold were at$2.40 per seat?

A. 150
B. 160
C. 200
D. 250
E. 300

PS20373

Solution:

We see that the revenue generated by the $1.80 seats is 1/3 x 600 x 1.8 = 200 x 1.8 =$360. Therefore, the remaining 400 seats generate a revenue of 1,020 - 360 = $660. Now, if we let m = the number of$1.20 seats sold and n = the number of $2.40 seats sold, we can create the equation: m + n = 400 and 1.2m + 2.4n = 660 We see that we need to solve for n. Since m = 400 - n, we have: 1.2(400 - n) + 2.4n = 660 480 - 1.2n + 2.4n = 660 1.2n = 180 n = 150 Answer: A Manager Joined: 26 Jan 2019 Posts: 120 Own Kudos [?]: 192 [0] Given Kudos: 333 Location: India Concentration: Finance, Technology GMAT 1: 500 Q42 V17 GMAT 2: 590 Q47 V26 Re: A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]
Let x,y,z be the number of seats costing $1.2,$1.8 and $2.4 respectively. Given: => 1.2x+1.8y+2.4z = 1020 or 2x+3y+4z= 1700-----------1) Given: x+y+z = 600-------------------2) Given: y = (x+y+z)/3 => 2y = x+z -------------------3) Using 2 and 3, y = 200 using 1, 2(x+y+z) +y+2z = 1700 =>2*600+200+2z = 1700 => z = 150 Senior Manager Joined: 14 Jul 2019 Status:Student Posts: 474 Own Kudos [?]: 372 [1] Given Kudos: 52 Location: United States Concentration: Accounting, Finance GMAT 1: 650 Q45 V35 GPA: 3.9 WE:Education (Accounting) A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]
1
Kudos
Bunuel
A theater with 600 seats sells tickets at $1.20,$1.80, or $2.40 per seat. On Wednesday evening, 1/3 of the tickets sold were at$1.80 per seat and the total receipts from the sale of 600 tickets was $1,020. How many of the tickets sold were at$2.40 per seat?

A. 150
B. 160
C. 200
D. 250
E. 300

PS20373

average price of ticket except the $1.8 ones = (1020-360)/400 = 660/400 = 66/40 = 33/20 = 1.65$
Applying allegation method:
1.20 ||||||||| 2.4
1.65
0.75 |||||||| 0.45
15 |||||||| 9
5 ||||||||||| 3

So, 2.40$ticket sold were = 400*3/8 = 150 A is the answer. Director Joined: 09 Jan 2020 Posts: 948 Own Kudos [?]: 239 [0] Given Kudos: 432 Location: United States Re: A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]
A theater sells 600 tickets at $1.20,$1.80, or $2.40 per seat. 1/3 of the tickets were sold at$1.80 = 200 tickets * 1.80 = 360

We have 400 tickets totaling $660 unaccounted for. Let $$400 - x$$ = tickets sold at$1.20
let $$x$$ = tickets sold at $2.40 $$1.20(400-x) + 2.40x = 660$$ $$480-1.2x + 2.40x = 660$$ $$480 + 1.2x = 660$$ $$1.2x = 180$$ $$x = 150$$ Answer is A. Tutor Joined: 17 Jul 2019 Posts: 1299 Own Kudos [?]: 1791 [0] Given Kudos: 66 Location: Canada GMAT 1: 780 Q51 V45 GMAT 2: 780 Q50 V47 GMAT 3: 770 Q50 V45 Re: A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]
Re: A theater with 600 seats sells tickets at $1.20,$1.80, or $2.40 per s [#permalink] Expert Reply ­Lots of ways to simplify once you have the system of equations up and running. Here's what I did: Re: A theater with 600 seats sells tickets at$1.20, $1.80, or$2.40 per s [#permalink]