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IanStewart
I'm guessing a bit what the question means, because the standard of writing is poor, but if the tens digit and units digit are both prime, and they multiply to the hundreds digit, then the tens and units digits can only be 2 or 3 (since if either was 5 or larger, we'd never get a product less than 10). I suppose you could now list the small number of possibilities: 422, 623, 632 and 933 and test each to determine which is correct. But if we take a three digit number ABC, and reverse its digits to get CBA, then if these numbers differ by roughly 300, then the digits A and C will differ by 3. So the number must be 623, and the tens digit must be 2.
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I Ian thank you very much for sharing your reasoning! It helped my a lot.
What I do not understand is when you say "reverse its digits to get CBA, then these numbers differ by roughly 300, then the digits A and C will differ buy three".
If CBA = 297, then ABC would = 792 which does not make any sense. None of the foud alternatives reverse to 297.
When I first read the question I understood the "reverse" number as the reciprocal.... Is this a huge misunderstanding? Or is it that the wording is confusing? I am not a native English speaker.

297 isn't either of the two numbers.
297 is the DIFFERENCE between the two numbers.
One of the two numbers could be called ABC, where A is hundreds place, B tens place and C the ones place.
The reverse of this number ABC means to create a new number CBA.
So the difference between these two numbers is:
ABC - CBA = 297
To facilitate this subtraction these numbers can be rewritten as:
(100A+10B+C) - (100C+10B+A)
which can be simplified to:
99(A-C) = 297.
Dividing through by 99:
A-C = 3 or A=C+3
So, because C is prime and A must be less than 10, these are the only choices for the pair:
A C
5 2
6 3
8 5
Now, it's further stipulated that A = B*C
So looking at the above options:
Can A=5 ?
5=B×2 NO B works
Can A=6 ?
6=B*3 YES. B=2
Can A=8 ?
8=B*5 NO B works
So, the only number that works is A=6 B=2 C=3
623