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# A total of 5 liters of gasoline is to be poured into two empty contain

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Re: A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
We need to divide 5lts in two containers such that bith are filled "to the same percent of their respective capacities"

Let's consider 50% i.e. 1/2 of the respective capacities. How many liters do we need to pour in the first container to get 50% filled? --> 1 liter

Similarly, how many liters do we need to pour in the second container to get 50%? --> 3 liters.

Now 1 + 3 = 4 liters while we have a total of 5 liters. In other words, the extra 1 liter will be divided into two containers.

So we can say that the second container will have a little more than 3 liters ---> (C)
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A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
Since x is a constant ratio. Let x be the ratio used to determine the amount (in liters) of gasoline.

2(x) + 6(x) = 5
8x = 5
x = 5/8

To determine amount in the 6-liter container, we multiply x with 6.

5/8 * 6 = $$3\frac{3}{4}$$

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Re: A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
Another way to solve (albeit, a little less efficient);

Consider that the proportions of both tanks have to be equal, therefore;

"Y liters / 6 liters of capacity = X liters / 2 liters of capacity"

And consider also;

"Y liters + X liters = 5 liters"

With this in mind, cross-multiply the first equation and solve for X. Once X has been isolated, substitute into the second equation to yield;

"Y = 15 / 4 = (3) (3 / 4)"

Therefore, our answer will be C.
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Re: A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
2x+6x = 5
x = 5/8

For 6 Ltr container: 6*(5/8) = 15/4 = Ans C
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A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
nalinnair wrote:
A total of 5 liters of gasoline is to be poured into two empty containers with capacities of 2 liters and 6 liters, respectively, such that both containers will be filled to the same percent of their respective capacities. What amount of gasoline, in liters, must be poured into the 6-liter container?

A. 4$$\frac{1}{2}$$

B. 4

C. 3$$\frac{3}{4}$$

D. 3

E. 1$$\frac{1}{4}$$

Quick, no-formula logic method in 1'15":

Since proportion needs to be equal, assume 50% of the 2L and 6L are filled, making the amount of gas to be 1+3 = 4L. This is not enough, so right away we can eliminate C and E.

To creep up to a total of 5L, we can up the proportion to 60%. Adding 10% to each of the initial amounts of gas, you get: 1+ 0.1 = 1.1, and 3+0.6=3.6, which is just under 5.

Closest answer to 3.6 is 3.75, making up for the gap to 5.
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Re: A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
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Re: A total of 5 liters of gasoline is to be poured into two empty contain [#permalink]
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