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Capthan
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A triangle 19 Apr 2008, 01:45
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Please help me with this one.



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sondenso
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A triangle 19 Apr 2008, 02:04
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Capthan
Please help me with this one.
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1. QS = 5, (pitago)
2. triangles QPS and PRS are similar. So PS/QS = PR/QP or 4/5 = PR/3 or PR=12/5
3. B

Anyway, due to my hurry up, correct me if I am wrong!
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Sunchaser20
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A triangle 19 Apr 2008, 05:23
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Capthan
Please help me with this one.
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(B) for me.
Can propose another way of solving: area of PQR = 1/2*QP*PS = 1/2*PR*QS
PR*QS = 12, while QS = 5
PR = 12/5
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rpmodi
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A triangle 02 May 2008, 15:28
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Sunchaser20
Capthan
Please help me with this one.
(B) for me.
Can propose another way of solving: area of PQR = 1/2*QP*PS = 1/2*PR*QS
PR*QS = 12, while QS = 5
PR = 12/5
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Can someone explain the solution again or may be elaborate on the solutions already given ? I didn't understand any of the above solutions
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lucyqin
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A triangle 02 May 2008, 16:34
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If PQ=3 and PS=4, then QS=5.
The key is to figure out what QR and RS are. QR+RS=QS=5.

QR^2 + PR^2 = 3^2 = 9
RS^2 + PR^2 = 4^2 = 16 ----->sub in RS = 5-QR-------->(5-QR)^2 + PR^2 =16

9 - QR^2 = 16 - (5-QR)^2
9 - QR^2 = 16 - 25 +10QR - QR^2
10QR = 18
QR = 9/5

QR^2 +PR^2 = 9
(9/5)^2 + PR^2 = 9
PR^2 = 144 / 25
PR = 12/5

So the answer is B. Hope this helps. Anyone is welcome to suggest an easier way.
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A triangle 04 May 2008, 09:38
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Create a mirror image of the triangle along QS and you have a rectangle. Using Pythagorean theorem, QS = 5 (3-4-5). Both line QS and the perpendicular imaginary QS will intersect almost at mid point 2.5

I use elimination process

A. \(\frac{9}{4}\) = 2.25 (not as close as 2.4)
B. \(\frac{12}{5}\) = 2.40 (closest to 2.5)
C. \(\frac{16}{5}\) = 3.20 (too far from 2.5 - eliminate)
D. \(\frac{15}{4}\) = 3.75 (too far from 2.5 - eliminate)
E. \(\frac{20}{3}\) = 6.67 (too far from 2.5 - eliminate)

Ans: B :-D



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
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