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08 Aug 2009, 09:54
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A Triangle ABC is given with 2 angles : x,y are angles lying across AC and AB ,respectively.
Is triangle ABC isosceles?
1/ X does not equal Y
2/ AB=2BC
Is triangle ABC isosceles?
1/ X does not equal Y
2/ AB=2BC
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08 Aug 2009, 10:23
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A Triangle ABC is given with 2 angles : x,y are angles lying across AC and AB ,respectively.
Is triangle ABC isosceles?
1/ X does not equal Y
2/ AB=2BC
E
each alone is not suff
both
side bc corresponds to the 3rd angle z, and as long as bc = 1/2 ab thus y>z, ie: x not = y , y not = z however we dont know the relation bet x,z.
Is triangle ABC isosceles?
1/ X does not equal Y
2/ AB=2BC
E
each alone is not suff
both
side bc corresponds to the 3rd angle z, and as long as bc = 1/2 ab thus y>z, ie: x not = y , y not = z however we dont know the relation bet x,z.
08 Aug 2009, 21:42
Kudos
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IMO C
Statement 1: x and y are not equal
so AB not equal to AC, But not sure about the other sides , so stmt1 insufficient
Statement 2: AB =2BC , so AB not equal to BC, but dont know about any other sides, so stmt2 insufficient
combining two statements,
AB not equal to AC,
AB not equal to BC,
so the remaining sides AC must be equal to BC for the triangle to be isoceles.
According to triangle inequality,
AC+BC must be greater than the third side AB
AC + BC > AB
AC + BC > 2BC ( given in question AB = 2BC)
AC > BC , so the triangle is not isoceles, hence the optio C.
Statement 1: x and y are not equal
so AB not equal to AC, But not sure about the other sides , so stmt1 insufficient
Statement 2: AB =2BC , so AB not equal to BC, but dont know about any other sides, so stmt2 insufficient
combining two statements,
AB not equal to AC,
AB not equal to BC,
so the remaining sides AC must be equal to BC for the triangle to be isoceles.
According to triangle inequality,
AC+BC must be greater than the third side AB
AC + BC > AB
AC + BC > 2BC ( given in question AB = 2BC)
AC > BC , so the triangle is not isoceles, hence the optio C.
, thanks...kudus 
