Here is the problem I have with this question. A triangle inscribed in a semi-circle will be a right triangle. So we know that 6 & 8 are the bases, which means the 3rd side is 10, a.k.a. the diameter of the semicircle. The formula for finding the perimeter of a semi-circle is \(\frac{1}{2}*d*pi\). The answer to this is 5pi, but that's not an option. 15 is close, but not exactly it either 5*pi(~3.14) = 15.7.

haichao wrote:

a triangle is inscribed in the semicircle. If the length of line segment AB is 8 and the length of line segment BC is 6, what is the length of arc ABC?

A. 15

B. 12

C. 10

D. 7

E. 5

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