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Bunuel
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A vessel is full of milk. 1/3 of the solution is taken out and replace 02 Dec 2021, 06:30
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74% (02:34) correct 26% (03:11) wrong based on 165 sessions

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A vessel is full of milk. 1/3 of the solution is taken out and replaced with water. This process is repeated thrice. At the end of it, if 16 liters of milk remains, how much water will be present in the vessel?

A. 17 ltr
B. 38 ltr
C. 39 ltr
D. 40 ltr
E. 42 ltr
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B
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A vessel is full of milk. 1/3 of the solution is taken out and replace 02 Dec 2021, 06:54
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Percentage Milk in the solution =2/3*2/3*2/3=8/27.
Remaining is water. For 27 parts of solution, 8 parts milk will be there. And remaining is water i.e., 19 parts of water.
Milk:water=8:19
For 16lts milk, 38lts water will be present.

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A vessel is full of milk. 1/3 of the solution is taken out and replace 20 Dec 2021, 03:25
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Bunuel
A vessel is full of milk. 1/3 of the solution is taken out and replaced with water. This process is repeated thrice. At the end of it, if 16 liters of milk remains, how much water will be present in the vessel?

A. 17 ltr
B. 38 ltr
C. 39 ltr
D. 40 ltr
E. 42 ltr

how can we make mixture diagram out of this question ?
kindly help :please:
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A vessel is full of milk. 1/3 of the solution is taken out and replace 20 Dec 2021, 04:41
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Let Milk = x water = 0

After first process:
Milk = 2x/3
Water = x/3

After second process:
Milk = (2/3)*(2x/3) = 4x/9
Water = (2/3)*(x/3) + x/3 = 5x/9

After third process:
Milk = (2/3)*(4x/9) = 8x/27
Water = (2/3)*(5x/9) + x/3 = 19x/27

Given: 8x/27 = 16
So, x = 54

So, water = 19x/27 = 38
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A vessel is full of milk. 1/3 of the solution is taken out and replace 23 Dec 2021, 05:35
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we start with 100% milk.
100% - 1/3(100%) ~ 67% milk left (33% water)
again 67% - 1/3(67%) ~ 45% milk left (55% water)
3rd time = 45% - 1/3(45%) ~ 30% milk left (70% water)
Now, given 30% = 16 Ltr
so 70% = 16/30 * 70 = 37.999.. = 38 ltr hence B is the ans.
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A vessel is full of milk. 1/3 of the solution is taken out and replace 24 Dec 2021, 17:31
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Bunuel
A vessel is full of milk. 1/3 of the solution is taken out and replaced with water. This process is repeated thrice. At the end of it, if 16 liters of milk remains, how much water will be present in the vessel?

A. 17 ltr
B. 38 ltr
C. 39 ltr
D. 40 ltr
E. 42 ltr

Breaking Down the Info:

The process of taking out 1/3 of the solution leaves only 2/3 of the solution left each time. By repeating this three times, we are left with \((\frac{2}{3})^3 = \frac{8}{27}\) of the solution.

Since we have 16 liters of milk left, the original volume must be \(\frac{27}{8}*16 = 54 \text{ L}\), and 54 - 16 = 38 L of that is water.

Answer: B
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A vessel is full of milk. 1/3 of the solution is taken out and replace 29 May 2024, 01:48
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C2 = C1 (V1/V2)^n
C2= final conc.
C1= initial conc.
V1 = initial volume after removal
v2= final volume after removal
Let v2 = V litres which is the final volume of the solution.
V1 = 1 - 1/3
V2 =1
16/V = 1 * (2/3) ^3
V=54

Hence water = 54 - 16 =38 lt.

KarishmaB is my approach my correct ?
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A vessel is full of milk. 1/3 of the solution is taken out and replace 25 Jun 2025, 01:38
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Bunuel
A vessel is full of milk. 1/3 of the solution is taken out and replaced with water. This process is repeated thrice. At the end of it, if 16 liters of milk remains, how much water will be present in the vessel?

A. 17 ltr
B. 38 ltr
C. 39 ltr
D. 40 ltr
E. 42 ltr
Using the replacement formula,

16 = (16+x)(1-1/3)^3
16 = 8/27(16+x)
x = 38
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