GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Oct 2018, 00:12

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# AB is perpendicular to CO. Is A or B closer to C?

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 50001
AB is perpendicular to CO. Is A or B closer to C?  [#permalink]

### Show Tags

17 Oct 2017, 23:40
00:00

Difficulty:

15% (low)

Question Stats:

86% (01:01) correct 14% (01:32) wrong based on 64 sessions

### HideShow timer Statistics

AB is perpendicular to CO. Is A or B closer to C?

(1) OA is less than OB.
(2) ACBD is not a parallelogram.

Attachment:

2017-10-18_1039.png [ 3.66 KiB | Viewed 713 times ]

_________________
PS Forum Moderator
Joined: 25 Feb 2013
Posts: 1216
Location: India
GPA: 3.82
AB is perpendicular to CO. Is A or B closer to C?  [#permalink]

### Show Tags

Updated on: 18 Oct 2017, 09:32
Bunuel wrote:

AB is perpendicular to CO. Is A or B closer to C?

(1) OA is less than OB.
(2) ACBD is not a parallelogram.

Attachment:
2017-10-18_1039.png

We need to find which is less $$AC$$ or $$BC$$

$$AC^2= OC^2+OA^2$$ and $$BC^2=OC^2+OB^2$$. subtract the two to get

$$AC^2-BC^2=OA^2-OB^2$$-------------------(1)

Statement 1: Statement itself is sufficient to answer the question, because position of C is fixed.

Mathematically it can be deduced as - given $$OA<OB$$, square both sides to get $$OA^2<OB^2$$, or $$OA^2-OB^2<0$$

Hence equation 1 becomes $$AC^2-BC^2<0 = > AC<BC$$. Sufficient

Statement 2: Nothing mentioned about distances of any point, hence insufficient

Option A

Originally posted by niks18 on 18 Oct 2017, 06:42.
Last edited by niks18 on 18 Oct 2017, 09:32, edited 1 time in total.
Status: Preparing for GMAT
Joined: 25 Nov 2015
Posts: 965
Location: India
GPA: 3.64
Re: AB is perpendicular to CO. Is A or B closer to C?  [#permalink]

### Show Tags

18 Oct 2017, 07:13
S1- OA>OB
OC is the same.
Therefore A is closer to C than B.
Sufficient
S2- No useful information.
Insufficient.
_________________

Please give kudos, if you like my post

When the going gets tough, the tough gets going...

Manager
Joined: 09 Aug 2017
Posts: 62
Location: United States
Concentration: Technology
GMAT 1: 640 Q44 V33
GMAT 2: 630 Q47 V29
WE: Research (Investment Banking)
Re: AB is perpendicular to CO. Is A or B closer to C?  [#permalink]

### Show Tags

23 Oct 2017, 18:07

St1, OA<OB
I viewed this problem as two triangles ACO and BCO. If leg OA is smaller than OB and they share a side in CO, a smaller OA will produce a smaller hypotenuse. Therefore point A is closer to C. Sufficient.

St2, ABCD is a parallelogram
Honestly, I have no idea what to do wit this information and assumed it was useless.
_________________

I'd love to hear any feedback or ways to improve my problem solving. I make a lot of silly mistakes. If you've had luck improving on stupid mistakes, I'd love to hear how you did it.

Also, I appreciate any kudos.

Re: AB is perpendicular to CO. Is A or B closer to C? &nbs [#permalink] 23 Oct 2017, 18:07
Display posts from previous: Sort by