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∆ABC is a right triangle in XY-plane such that AB is parallel to the
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02 Jan 2019, 00:10
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13
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Difficulty:
95% (hard)
Question Stats:
24% (02:30) correct 76% (02:57) wrong based on 72 sessions
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∆ABC is a right triangle in XY-plane such that AB is parallel to the y-axis and the right angle is at B. The x and y-coordinates of A, B, and C are to be non-zero integers that satisfy the inequalities -4 (<=) x (<=) 5 (read the bracketed sign as less than equal to)and -2 <= y <= 5. Given these restrictions, how many different triangles can be constructed?
Re: ∆ABC is a right triangle in XY-plane such that AB is parallel to the
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02 Jan 2019, 01:33
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Absolute 700+ level question. Please use concepts of Coordinate Geometer and Permutation & Combination to solve the problem.
Give that A, B, and C are non-zero integers and satisfy the inequalities -4 ≤ x ≤ 5 and -2≤ y ≤ 5. Hence x can have 9 possible values and y can have 7 possible values (zero cannot be a possible value since A, B, C are non-zero integers).
Step 1: There are 9 possible values of x coordinate and 7 possible values of y coordinate. Hence, point B (the right angle vertex) can be 9x7 = 63 possible values of coordinate B.
Step 2: Since AB is parallel to the y axis, point A has the same x coordinate but different y coordinate as point B. Since point B has already has 80 different values, we can have 7-1 = 6 possible values of coordinate A, each corresponding to those 80 possible values of coordinate B.
Step 3: Since ABC is a right angle triangle, point c has the same y coordinate but different x coordinate as point B. Since point B has already has 80 different values, we can have 9-1 = 8 possible values of coordinate C, each corresponding to those 80 possible values of coordinate B.
Therefore, the total possible number of triangle is the same as the the total possible values of A, B, & C, i.e. 63x6x8 = 3024 ways
Hence, the Correct Answer is Option A. 3,024 _________________
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Re: ∆ABC is a right triangle in XY-plane such that AB is parallel to the
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03 Jan 2019, 06:58
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ATS: Coordinates of A,B and C are non-zero integers AB is parallel to Y-axis BC is parallel to X-axis
As vertex B is common to both sides (AB and BC), lets start with B: Options along Y-axis= (-2 to +5 excluding 0) 7 Options along X-axis= (-4 to +5 excluding 0) 9 Total= 63
Vertex A: Out of 7 options along Y-axis, one is taken by B, so 6 left for A.
Vertex C: Out of 9 options along X-axis, one is taken by B, so 8 left for A.
Total possible triangles within the coordinate grid: 63x6x8= 3024, Ans A
Re: ∆ABC is a right triangle in XY-plane such that AB is parallel to the
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24 Jan 2019, 10:44
DisciplinedPrep wrote:
Step 2: Since AB is parallel to the y axis, point A has the same x coordinate but different y coordinate as point B. Since point B has already has 80 different values, we can have 7-1 = 6 possible values of coordinate A, each corresponding to those 80 possible values of coordinate B.
Step 3: Since ABC is a right angle triangle, point c has the same y coordinate but different x coordinate as point B. Since point B has already has 80 different values, we can have 9-1 = 8 possible values of coordinate C, each corresponding to those 80 possible values of coordinate B.
Shouldn't this be 63 possible values of B instead of 80?
gmatclubot
Re: ∆ABC is a right triangle in XY-plane such that AB is parallel to the
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24 Jan 2019, 10:44
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24% (02:30) correct 
