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ABCD is a square and one of its sides AB is also a chord of the circle

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ABCD is a square and one of its sides AB is also a chord of the circle  [#permalink]

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New post Updated on: 15 Jul 2019, 04:05
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

81% (00:43) correct 19% (00:32) wrong based on 21 sessions

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Originally posted by Bunuel on 09 Oct 2018, 01:15.
Last edited by SajjadAhmad on 15 Jul 2019, 04:05, edited 2 times in total.
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Re: ABCD is a square and one of its sides AB is also a chord of the circle  [#permalink]

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New post Updated on: 09 Oct 2018, 01:26
Since the radii of the circle and the chord form a right angled triangle, the length of the chord becomes 3\sqrt{2}.

Further, the chord is the side of the square. Using the formula for the area of a square, the area is 3\sqrt{2}*3\sqrt{2}= 18 sq units. Answer E.

Originally posted by SushiVoyage on 09 Oct 2018, 01:22.
Last edited by SushiVoyage on 09 Oct 2018, 01:26, edited 1 time in total.
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Re: ABCD is a square and one of its sides AB is also a chord of the circle  [#permalink]

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New post 09 Oct 2018, 01:24
Bunuel wrote:
Image
ABCD is a square and one of its sides AB is also a chord of the circle as shown in the figure. What is the area of the square?


(A) 3

(B) 9

(C) 12

(D) 12√2

(E) 18

Attachment:
figure.jpg



AB is basically the side hypontuse of the triangle and side of a square.


\(AB^2 = 3^2 + 3^2\)
AB = \(\sqrt{18}\)

Area of the square = AB*AB = \(\sqrt{18*18}\) = 18

The best answer is E.
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Re: ABCD is a square and one of its sides AB is also a chord of the circle  [#permalink]

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New post 09 Oct 2018, 01:44
OA^2+OB^2=AB^2-Using pythogoras theorem

Therefore, 3^2+3^2=AB^2
AB=√18=3√2
We've got one side of the square.
Area of the square= 3√2 × 3√2 =18

So the answer is option E

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Re: ABCD is a square and one of its sides AB is also a chord of the circle   [#permalink] 09 Oct 2018, 01:44
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ABCD is a square and one of its sides AB is also a chord of the circle

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