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27 Apr 2020, 14:21
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:32) correct
23%
(01:39)
wrong
based on 1536
sessions
History
Date
Time
Result
Not Attempted Yet
A certain financial analyst defines the “volatility” of a stock during a given week to be the result of the following procedure: find the absolute value of the difference in the stock's closing price for each pair of consecutive days in the week and then find the average (arithmetic mean) of these 4 values. What is the volatility of Stock X during the week shown in the table?
A. 0.50
B. 1.80
C. 2.00
D. 2.25
E. 2.50
PS28580.02
Attachment:
2020-04-28_0119.png [ 17.6 KiB | Viewed 17954 times ]
27 Apr 2020, 14:34
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\(V = \frac{|19-21|+|22-19|+|24.5-22|+|23-24.5|}{4}\)
\(V = \frac{2+3+2.5+1.5}{4 }= \frac{9}{4} =2.25\)
\(V = \frac{2+3+2.5+1.5}{4 }= \frac{9}{4} =2.25\)
parkhydel
General Discussion
06 Mar 2022, 07:18
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parkhydel
Absolute difference from Monday to Tuesday = |19 - 21| = 2
Absolute difference from Tuesday to Wednesday = |22 - 19| = 3
Absolute difference from Wednesday to Thursday = |24.5 - 22| = 2.5
Absolute difference from Thursday to Friday = |23 - 24.5| = 1.5
Average of the absolute differences = (2 +3 + 2.5 + 1.5)/4 = 9/4 = 2.25
Answer: D
