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# Adam, Bob, Carol, Diane, and Ed are all sitting on a bench. If Adam an

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Manager
Joined: 02 Jun 2015
Posts: 191
Location: Ghana

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03 Mar 2017, 06:11
1
4
00:00

Difficulty:

35% (medium)

Question Stats:

61% (01:17) correct 39% (01:04) wrong based on 65 sessions

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Adam, Bob, Carol, Diane, and Ed are all sitting on a bench. If Adam and Diane must sit next to each other and Bob and Carol must sit next to each other, how many different seating arrangements are possible on the bench?

A) 3
B) 6
C) 8
D) 12
E) 24

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Concentration: Strategy, General Management
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Re: Adam, Bob, Carol, Diane, and Ed are all sitting on a bench. If Adam an  [#permalink]

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03 Mar 2017, 08:45
Adam and Diane = 1 group
Bob and Carol = 1 group

In total there are 2 groups and 1 person.

Number of ways of arranging 2 groups and 1 person = 3! = 6 ways
In each group there are 2 ways of sitting --> 2 * 2 = 4 ways

Total number of ways = 6 * 4 = 24

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Re: Adam, Bob, Carol, Diane, and Ed are all sitting on a bench. If Adam an  [#permalink]

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03 Mar 2017, 09:49
duahsolo wrote:
Adam, Bob, Carol, Diane, and Ed are all sitting on a bench. If Adam and Diane must sit next to each other and Bob and Carol must sit next to each other, how many different seating arrangements are possible on the bench?

A) 3
B) 6
C) 8
D) 12
E) 24

(AD) = 2! ways = 2 ways
(BC) = 2! ways = 2 ways

(AD), (BC) & E = 3! ways = 6 ways

So, total number of ways will be 6*2*2 = 24 ways

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Abhishek....

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Re: Adam, Bob, Carol, Diane, and Ed are all sitting on a bench. If Adam an &nbs [#permalink] 03 Mar 2017, 09:49
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