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Adam bought a box of 15 Apples out of which exactly 5 were Green and r

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Manager
Joined: 26 Dec 2018
Posts: 142
Location: India
Adam bought a box of 15 Apples out of which exactly 5 were Green and r  [#permalink]

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12 Jan 2019, 10:57
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Difficulty:

75% (hard)

Question Stats:

50% (02:43) correct 50% (02:53) wrong based on 34 sessions

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Adam bought a box of 15 Apples out of which exactly 5 were Green and rest were Red. He took out 4 Apples at random. What is the probability that atleast 2 out of 4 Apples selected were Green?

A. 3/91
B. 13/91
C. 30/91
D. 31/91
E. 37/91

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VP
Joined: 09 Mar 2018
Posts: 1003
Location: India
Adam bought a box of 15 Apples out of which exactly 5 were Green and r  [#permalink]

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12 Jan 2019, 11:40
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UB001 wrote:
Adam bought a box of 15 Apples out of which exactly 5 were Green and rest were Red. He took out 4 Apples at random. What is the probability that atleast 2 out of 4 Apples selected were Green?

A. 3/91
B. 13/91
C. 30/91
D. 31/91
E. 37/91

G=5, R= 10

probability that atleast 2 out of 4 Apples selected were Green = $$\frac{{Favorable outcomes}}{{Total_Outcomes}}$$

If you solve this $$\frac{{5c2*10c2 + 5c3*10c1 + 5c4}}{{15c4}}$$

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Manager
Joined: 23 Apr 2016
Posts: 59
Location: Singapore
Concentration: Entrepreneurship, Technology
WE: Other (Internet and New Media)
Re: Adam bought a box of 15 Apples out of which exactly 5 were Green and r  [#permalink]

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13 Jan 2019, 04:31
IMO E

Cheers!
Shantanu Sharma
MBA and Beyond Consulting
KanishkM wrote:
UB001 wrote:
Adam bought a box of 15 Apples out of which exactly 5 were Green and rest were Red. He took out 4 Apples at random. What is the probability that atleast 2 out of 4 Apples selected were Green?

A. 3/91
B. 13/91
C. 30/91
D. 31/91
E. 37/91

G=5, R= 10

probability that atleast 2 out of 4 Apples selected were Green = $$\frac{{Favorable outcomes}}{{Total_Outcomes}}$$

If you solve this $$\frac{{5c2*10c2 + 5c3*10c1 + 5c4}}{{15c4}}$$

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Re: Adam bought a box of 15 Apples out of which exactly 5 were Green and r   [#permalink] 13 Jan 2019, 04:31
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