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# Alex and Scott are reading copies of the same book, each at his own co

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Math Expert
Joined: 02 Sep 2009
Posts: 59622
Alex and Scott are reading copies of the same book, each at his own co  [#permalink]

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27 Apr 2017, 02:39
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1
00:00

Difficulty:

15% (low)

Question Stats:

80% (01:36) correct 20% (02:27) wrong based on 96 sessions

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Alex and Scott are reading copies of the same book, each at his own constant rate. Alex reads 60 pages per hour and started reading at 1:00 p.m. while Scott reads 40 pages per hour and started reading at 12:30 p.m. What time will they be reading the same page?

A. 2:00 p.m.
B. 2:15 p.m.
C. 3:30 p.m.
D. 4:00 p.m.
E. 4:15 p.m.

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Alex and Scott are reading copies of the same book, each at his own co  [#permalink]

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27 Apr 2017, 03:33
2

Let y be the time spent by both of them to read the book.

$$60y = 40*(\frac{y+1}{2})$$ since Scott has read for an extra half hour

Solving for y, we get 20y = 20 -> y = 1

Since they start at 1PM, the time at which they are reading the same page is 2 PM(Option A)
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Re: Alex and Scott are reading copies of the same book, each at his own co  [#permalink]

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27 Apr 2017, 04:02
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1
At 1.00 pm Scott would have read 40/2 = 20 pages

Relative reading speed = 60 - 40 = 20

Time taken for Alex to catch up with Scott = 20/20 = 1 hour --> 1.00 pm + 1 = 2.00 pm

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Joined: 06 Dec 2016
Posts: 227
Re: Alex and Scott are reading copies of the same book, each at his own co  [#permalink]

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27 Apr 2017, 11:11
Process elimination is a life saver.
First calculcate how many pages Scott has read by 1pm
0.5 x 40 = 20

Then look at the answer choices and do process eliminaiton

By 2 pm - Scott = 20 x (1x 40) = 60 pgs

Alex = 60x 1 = 60

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Re: Alex and Scott are reading copies of the same book, each at his own co  [#permalink]

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22 Nov 2019, 12:49
Bunuel wrote:
Alex and Scott are reading copies of the same book, each at his own constant rate. Alex reads 60 pages per hour and started reading at 1:00 p.m. while Scott reads 40 pages per hour and started reading at 12:30 p.m. What time will they be reading the same page?

A. 2:00 p.m.
B. 2:15 p.m.
C. 3:30 p.m.
D. 4:00 p.m.
E. 4:15 p.m.

If we let t = the amount of time that Alex has read, then (t + ½) = the amount of time that Scott has read. We can create the equation:

60t = 40(t + 1/2)

60t = 40t + 20

20t = 20

t = 1

So, they read the same page at 2pm.

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Re: Alex and Scott are reading copies of the same book, each at his own co   [#permalink] 22 Nov 2019, 12:49
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