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Ambrose and Davis arranged to meet along a path from Vista View to Bat 05 May 2017, 04:54
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35% (medium)

Question Stats:

76% (02:09) correct 24% (02:32) wrong based on 222 sessions

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Ambrose and Davis arranged to meet along a path from Vista View to Bathing Point, Ambrose starts at 10 a.m. walking from Vista View toward Bathing Point an average speed of 4 miles per hour. If Davis starts walking the 76 miles from Bathing Point to Vista View at 9 a.m. walking at 6 miles per hour, how far from Vista View will they meet?

A. 48
B. 42
C. 30.4
D. 28
E. 24.4
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D
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Ambrose and Davis arranged to meet along a path from Vista View to Bat 05 May 2017, 07:49
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Ambrose: 4 mph and starts at 10 am
Davis: 6 mph and starts at 9 am
Distance = 76

When they meet, distance covered by Ambrose + distance covered by Davis = 76
4t + 6t + 6 = 76
10t = 70
t = 7

Distance from Vista View = 4*7 = 28

Answer: D
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Ambrose and Davis arranged to meet along a path from Vista View to Bat 05 May 2017, 09:40
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Bunuel
Ambrose and Davis arranged to meet along a path from Vista View to Bathing Point, Ambrose starts at 10 a.m. walking from Vista View toward Bathing Point an average speed of 4 miles per hour. If Davis starts walking the 76 miles from Bathing Point to Vista View at 9 a.m. walking at 6 miles per hour, how far from Vista View will they meet?

A. 48
B. 42
C. 30.4
D. 28
E. 24.4
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Distance between the 2 points is 76 miles...

Distance covered by Davis by 10 AM is 6 miles, thus the distance between the 2 points at 10 Am is 70 Miles...

Relative speed of the 2 bodies moving towards each other is 6 miles/hr + 4 miles/hr = 10 miles/hr

So, the Time taken by the 2 bodies to meet will be 70/10 = 7 hours..

Thus, the distance from Vista View when the 2 bodies meet is 7*4 = 28 Miles...

Hence, answer must be (D) 28 Miles !
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Ambrose and Davis arranged to meet along a path from Vista View to Bat 07 May 2017, 11:06
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Davis covered 6 miles in 1 hour.
Rest 70 miles is covered at a relative speed of (6+4) miles/hr. Hence, 70/10 = 7 hours until they meet.
Distance from Vista View is the speed at which Ambrose was travelling. Hence, 7*4 = 28 miles
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Ambrose and Davis arranged to meet along a path from Vista View to Bat 12 May 2017, 13:12
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Bunuel
Ambrose and Davis arranged to meet along a path from Vista View to Bathing Point, Ambrose starts at 10 a.m. walking from Vista View toward Bathing Point an average speed of 4 miles per hour. If Davis starts walking the 76 miles from Bathing Point to Vista View at 9 a.m. walking at 6 miles per hour, how far from Vista View will they meet?

A. 48
B. 42
C. 30.4
D. 28
E. 24.4
Show more

We have a converging problem in which we can use the following formula:

distance of Ambrose + distance of Davis = total distance = 76

We are given that Ambrose starts walking at 10 a.m. at a rate of 4 mph and that Davis starts walking at 9 a.m. at a rate of 6 mph. Thus, we can let Ambrose’s time = t and Davis’s time = t + 1.

Thus, Davis’s distance = 6(t + 1) = 6t + 6 and Ambrose’s distance = 4t. Plugging this into our original equation, we have:

6t + 6 + 4t = 76

10t + 6 = 76

10t = 70

t = 7

Thus, when the two met, Ambrose had traveled 7 x 4 = 28 miles, so they were 28 miles from Vista View.

Answer: D
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Ambrose and Davis arranged to meet along a path from Vista View to Bat 21 Dec 2024, 13:25
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