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arjtryarjtry
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Without solving.. this problem I chose Answer in 10 sec.. :lol: that is 120..
I will this logic when I don't have time.. (Educated Guess)

Question talking about 400 students.. Given info is in percentage.. so generally everyone .. pick 100 as number of students..then solve equation.
So answer would be some number say "M%' but answer would be 4M.

only 30 and 120 are in that ratio (1:4) ..

After solving I got the same answer.

100 = A+B+C - (x+y+z)-2(T)

100= 160-(30+y+z)-2(T)
y= 60-30-z-2T

y is maximum when z and t are zeros.

Y=30%

y =120
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x2suresh
Without solving.. this problem I chose Answer in 10 sec.. :lol: that is 120..
I will this logic when I don't have time.. (Educated Guess)

Question talking about 400 students.. Given info is in percentage.. so generally everyone .. pick 100 as number of students..then solve equation.
So answer would be some number say "M%' but answer would be 4M.

only 30 and 120 are in that ratio (1:4) ..

After solving I got the same answer.

100 = A+B+C - (x+y+z)-2(T)

100= 160-(30+y+z)-2(T)
y= 60-30-z-2T

y is maximum when z and t are zeros.

Y=30%

y =120

how did you get 160?
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arjtryarjtry
x2suresh
Without solving.. this problem I chose Answer in 10 sec.. :lol: that is 120..
I will this logic when I don't have time.. (Educated Guess)

Question talking about 400 students.. Given info is in percentage.. so generally everyone .. pick 100 as number of students..then solve equation.
So answer would be some number say "M%' but answer would be 4M.

only 30 and 120 are in that ratio (1:4) ..

After solving I got the same answer.

100 = A+B+C - (x+y+z)-2(T)

100= 160-(30+y+z)-2(T)
y= 60-30-z-2T

y is maximum when z and t are zeros.

Y=30%

y =120

how did you get 160?


For get about my solution... I was dumb yesterday... Long day.. I answered while I was in half sleep.. even I didn't read the questions properly.


assume we have 100 students.

No of students who study Sociology or Mathematics
=S+M-both(S and M) = 56+44-30=70

to get the max students who study Biology= 100-70=30%

total number=400*0.3=120
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arjtryarjtry
Among 400 students, 56% study sociology, 44% study mathematics and 40% study biology. If 30% of students study both mathematics and sociology, what is the largest possible number of students who study biology but do not study either mathematics or sociology?

A. 30
B. 90
C. 120
D. 172
E. 188

im getting 120 as the bio students, but the question says 40% whihc is 160.
what is the mistake?


who study biology but do not study either mathematics or sociology. Does this mean there is no one who studies all three??
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arjtryarjtry
Among 400 students, 56% study sociology, 44% study mathematics and 40% study biology. If 30% of students study both mathematics and sociology, what is the largest possible number of students who study biology but do not study either mathematics or sociology?

A. 30
B. 90
C. 120
D. 172
E. 188

im getting 120 as the bio students, but the question says 40% whihc is 160.
what is the mistake?

160 should be the correct answer. If the students taking Biology do not take any other course (possible with the given percentages), then we have 40% of students as the solution.

EDIT: Just realized my mistake. 120 should be the answer. 56 + 44 - 30 = 70%. That leaves 30% who do not take either mathematics or sociology. My earlier mistake was taking an entire overlap between Mathematics and Sociology students (as in every sociology student was also taking mathematics, which which case the overlap was 0% not 30%)
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What is the source of this question?
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It should be C. 120

Total student taking math and socio= (56 + 44 -30 )%= 70 %

So, maximum bio students ( no need to consider socio or math students.. as not other conditions are given)= 30 % of 400 = 120
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ssandeepan
It should be C. 120

Total student taking math and socio= (56 + 44 -30 )%= 70 %

So, maximum bio students ( no need to consider socio or math students.. as not other conditions are given)= 30 % of 400 = 120
This is a good approach
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How do you still explain the fact that the question says 40% of 400 for Bio. which comes to 160 students? The answer should definitely be 120 and the only way to account for that is to assume that some students( actually 40) study all three subjects. If you read the question carefully, it is no where discounting the fact that there could be students studying all 3 subjects.



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