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Bunuel
Among all the 24 different positive four-digit integers formed out of 6, 7, 8, 9, at which place will 8697 rank from the least to the greatest?

A. 11
B. 12
C. 13
D. 14
E. 15

6 _ _ _ = 3! ways

7 _ _ _ = 3! ways

8 6 _ _ = 1 way

Total number prior to 8697 = 13

So 8697 is at the 14th place.

Option D
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We have the digits 6,7,8,9

We need to start from the least to the greatest

The lowest number will obviously start from 6

6_ _ _ [here we can fill in 7,8,9]
hence, the total possible combinations of numbers starting from 6 => 3!

Then we will have numbers starting from 7

7_ _ _ [here we can fill 6,8,9]
hence, the total possible combinations of numbers starting from 7 => 3!

Then we will have numbers starting from 8

Now, note that we need to find the rank of the number 8697

And the first number starting from 8 will have the next digit as 6 [again because we have to go from the lowest to the greatest]

hence, will have 86_ _ [here we can fill 7,9]

Because we have to rank from the lowest to the greatest the next number will be 8679
And now, the next number will be 8697 [exactly what we need]

hence the rank of 8697 = 3!+3!+1+1 = 6+6+1+1 = 14


P.S. The ranks of the numbers are as follows

6789
6798
6879
6897
6978
6987
7689
7698
7869
7896
7968
7986
8679
8697 -> 14th
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Hello from the GMAT Club BumpBot!

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