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# An ant walks an average of 500 meters in 12 minutes. A beetle walks 15

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Math Expert
Joined: 02 Sep 2009
Posts: 51121
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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11 Jul 2016, 11:30
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Difficulty:

25% (medium)

Question Stats:

81% (02:03) correct 19% (02:45) wrong based on 141 sessions

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An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.125
B. 2.5
C. 2.775
D. 3.2
E. 3.5

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Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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11 Jul 2016, 13:19
1
Y am I getting 2.125 ?.. not even in the options.

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Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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11 Jul 2016, 23:05
1
shashanksagar wrote:
Y am I getting 2.125 ?.. not even in the options.

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the ant walks an average of 500 meters in 12 minutes
or,
500 meters in 1/5 hours

the beetle walks 15% less distance = 500-75=425 meters in 12 minutes
or,
0.425 km in 12/60 = 1/5 hours

speed = 0.425*5 = 2.125 km/h

I guess option A should be 2.125
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Joined: 08 Jul 2017
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Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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22 Oct 2017, 06:54
1
I did a bit of dimensional analysis initially.

(500m/12 min) * (60 min/1hr) * (1km/1000m) = 5km/2hr = 2.5km/hr.

Remember that the answers are increasing in rates. Given that the beetle must be walking slower than 2.5km/hr and there is only one answer with a lower rate than 2.5km/hr, (Answer choice A) that one must be the answer.

If you had to solve for it, since we know the beetle's speed is 15% less (10% + 5%), just determine 15% and subtract from 2.5km/hr. 10% of 2.5 = 0.25,and half of that is 0.125.

Then we're looking at [2.5 - (0.25 + .125)] or (2.5 - 0.375) = 2.125 which should be the answer, but maybe it's a typo?
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Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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22 Oct 2017, 08:23
1
Bunuel wrote:
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.215.
B. 2.5.
C. 2.775.
D. 3.2.
E. 3.5.

Bunuel , I, too, calculate the answer as 2.125 km/hr. I think there might be a typo in answer A.

Ant: $$\frac{500m}{12min}$$

Beetle walks 15 percent less distance in same time. (500 * .85 ) = 425 m

Beetle: $$\frac{425m}{12min} *\frac{60min}{1hr}* \frac{1km}{1000m}$$ =

$$\frac{425}{200}$$ = 2.125 km/hr

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Joined: 02 Sep 2009
Posts: 51121
Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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23 Oct 2017, 00:18
1
genxer123 wrote:
Bunuel wrote:
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.215.
B. 2.5.
C. 2.775.
D. 3.2.
E. 3.5.

Bunuel , I, too, calculate the answer as 2.125 km/hr. I think there might be a typo in answer A.

Ant: $$\frac{500m}{12min}$$

Beetle walks 15 percent less distance in same time. (500 * .85 ) = 425 m

Beetle: $$\frac{425m}{12min} *\frac{60min}{1hr}* \frac{1km}{1000m}$$ =

$$\frac{425}{200}$$ = 2.125 km/hr

Typo edited. Thank you all.
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Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15  [#permalink]

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26 Oct 2017, 14:30
Bunuel wrote:
An ant walks an average of 500 meters in 12 minutes. A beetle walks 15% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?

A. 2.125
B. 2.5
C. 2.775
D. 3.2
E. 3.5

The rate of the beetle in meters per minute is (0.85 x 500)/12 = 425/12.

Since 1 hour = 60 minutes and 1 km = 1000 meters, the rate in km per hour is:

425/12 x 60 / 1000 = 425 x 5 / 1000 = 2.125

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Re: An ant walks an average of 500 meters in 12 minutes. A beetle walks 15 &nbs [#permalink] 26 Oct 2017, 14:30
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