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TGC
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An eccentric casino owner decides that his casino should Updated on: 19 Mar 2013, 00:26
Originally posted by TGC on 19 Mar 2013, 00:12.
Last edited by Bunuel on 19 Mar 2013, 00:26, edited 1 time in total.
Edited the question.
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15% (low)

Question Stats:

83% (01:39) correct 17% (01:16) wrong based on 400 sessions

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An eccentric casino owner decides that his casino should only use chips in $5 and $7 denominations. Which of the following amount cannot be paid out using these chips?

A. $31
B. $29
C. $26
D. $23
E. $21
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D
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TGC
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Concentration: General Management, General Management
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An eccentric casino owner decides that his casino should 19 Mar 2013, 00:13
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I have a query in this question?

As there it is not mentioned that there can be no chips for particular denomination.

Eqn: 5x + 7y

My query is can we have either x = 0 or y=0 or both?
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Bunuel
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An eccentric casino owner decides that his casino should 19 Mar 2013, 00:33
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targetgmatchotu
An eccentric casino owner decides that his casino should only use chips in $5 and $7 denominations. Which of the following amount cannot be paid out using these chips?

A. $31
B. $29
C. $26
D. $23
E. $21

I have a query in this question?

As there it is not mentioned that there can be no chips for particular denomination.

Eqn: 5x + 7y

My query is can we have either x = 0 or y=0 or both?
Show more

Yes, the number of 5 or/and 7 dollar chips can be zero, however both being zero mean that the casino is paying out $0, which is not realistic.

Each option but D can be represented as the sum of a multiple of 5 and a multiple of 7:

A. $31 = 7*3 + 5*2
B. $29 = 7*2 + 5*3
C. $26 = 7*3 + 5*1
E. $21 = 7*3

Answer: D.

Hope it's clear.
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An eccentric casino owner decides that his casino should 09 Jul 2016, 13:20
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Bunuel
targetgmatchotu
An eccentric casino owner decides that his casino should only use chips in $5 and $7 denominations. Which of the following amount cannot be paid out using these chips?

A. $31
B. $29
C. $26
D. $23
E. $21

I have a query in this question?

As there it is not mentioned that there can be no chips for particular denomination.

Eqn: 5x + 7y

My query is can we have either x = 0 or y=0 or both?

Yes, the number of 5 or/and 7 dollar chips can be zero, however both being zero mean that the casino is paying out $0, which is not realistic.

Each option but D can be represented as the sum of a multiple of 5 and a multiple of 7:

A. $31 = 7*3 + 5*2
B. $29 = 7*2 + 5*3
C. $26 = 7*3 + 5*1
E. $21 = 7*3

Answer: D.

Hope it's clear.
Show more

Bunel,

I understood the above explanation. But is there is any other logic we can use to get the answer quick?

Thanks,
Arun
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Bunuel
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An eccentric casino owner decides that his casino should 09 Jul 2016, 23:30
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ArunpriyanJ
Bunuel
targetgmatchotu
An eccentric casino owner decides that his casino should only use chips in $5 and $7 denominations. Which of the following amount cannot be paid out using these chips?

A. $31
B. $29
C. $26
D. $23
E. $21

I have a query in this question?

As there it is not mentioned that there can be no chips for particular denomination.

Eqn: 5x + 7y

My query is can we have either x = 0 or y=0 or both?

Yes, the number of 5 or/and 7 dollar chips can be zero, however both being zero mean that the casino is paying out $0, which is not realistic.

Each option but D can be represented as the sum of a multiple of 5 and a multiple of 7:

A. $31 = 7*3 + 5*2
B. $29 = 7*2 + 5*3
C. $26 = 7*3 + 5*1
E. $21 = 7*3

Answer: D.

Hope it's clear.

Bunel,

I understood the above explanation. But is there is any other logic we can use to get the answer quick?

Thanks,
Arun
Show more

Trial and error is pretty much the only way to solve this question.
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An eccentric casino owner decides that his casino should 06 Feb 2025, 17:00
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