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An employer has 6 applicants for a programming position

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An employer has 6 applicants for a programming position [#permalink]

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New post 10 Sep 2016, 07:10
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Question Stats:

79% (00:43) correct 21% (00:50) wrong based on 67 sessions

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An employer has 6 applicants for a programming position and 4 applicants for a manager position. If the employer must hire 3 programmers and 2 managers, what is the total number of ways the employer can make the selection?

a) 1,490
b) 132
c) 120
d) 60
e) 23
[Reveal] Spoiler: OA

Kudos [?]: 19 [0], given: 119

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Status: Aiming MBA
Joined: 18 Jul 2015
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Re: An employer has 6 applicants for a programming position [#permalink]

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New post 10 Sep 2016, 07:21
azamaka wrote:
An employer has 6 applicants for a programming position and 4 applicants for a manager position. If the employer must hire 3 programmers and 2 managers, what is the total number of ways the employer can make the selection?

a) 1,490
b) 132
c) 120
d) 60
e) 23


6C3 * 4C2 = 120. Answer C.
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Re: An employer has 6 applicants for a programming position [#permalink]

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New post 19 Nov 2017, 14:49
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azamaka wrote:
An employer has 6 applicants for a programming position and 4 applicants for a manager position. If the employer must hire 3 programmers and 2 managers, what is the total number of ways the employer can make the selection?

a) 1,490
b) 132
c) 120
d) 60
e) 23


Take the task of selecting employees and break it into stages.

Stage 1: Select 3 programmers to hire
Since the order in which we select the programmers does not matter, we can use combinations.
We can select 3 programmers from 6 programmers in 6C3 ways (20 ways)
So, we can complete stage 1 in 20 ways

If anyone is interested, we have a free video on calculating combinations (like 6C3) in your head: http://www.gmatprepnow.com/module/gmat- ... /video/789

Stage 2: Select 2 managers to hire
Once again, we can use combinations
We can select 2 managers from 4 applicants in 4C2 ways (6 ways)
So, we can complete stage 2 in 6 ways

By the Fundamental Counting Principle (FCP), we can complete the 2 (and thus hire all of the people) in (20)(6) ways (= 120 ways)

Answer: C

Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. So, be sure to learn it.

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Re: An employer has 6 applicants for a programming position [#permalink]

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New post 22 Nov 2017, 12:25
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azamaka wrote:
An employer has 6 applicants for a programming position and 4 applicants for a manager position. If the employer must hire 3 programmers and 2 managers, what is the total number of ways the employer can make the selection?

a) 1,490
b) 132
c) 120
d) 60
e) 23


The programmers can be selected in 6C3 = 6!/3![(6-3)!] = (6 x 5 x 4)/3! = (6 x 5 x 4)/(3 x 2) = 20 ways.

The managers can be selected in 4C2 = 4!/[2!(4-2)!] = (4 x 3)/2! = 6 ways.

Thus, the total number of ways to select the group is 20 x 6 = 120.

Answer: C
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Kudos [?]: 971 [1], given: 5

Re: An employer has 6 applicants for a programming position   [#permalink] 22 Nov 2017, 12:25
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