Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
07 Mar 2023, 10:28
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
69% (03:25) correct
31%
(03:10)
wrong
based on 253
sessions
History
Date
Time
Result
Not Attempted Yet
An express train traveled at an average speed of 100 kilometers per hour, stopping for 3 minutes after every 75 kilometers. A local train traveled at an average speed of 50 kilometers, stopping for 1 minute after every 25 kilometers. If the trains began traveling at the same time, how many kilometers did the local train travel in the time it took the express train to travel 600 kilometers?
A. 300
B. 305
C. 307.5
D. 1200
E. 1236
A. 300
B. 305
C. 307.5
D. 1200
E. 1236
08 Mar 2023, 07:02
Kudos
Bookmarks
Bunuel
Express train
R*T=D
100*x=600
x=6
but we need to add the time that the train stop every 75 km which is 3 min.
600 km divided by 75km = 8 which means that the train made 7 stops.
7*3min=21 min
\(\frac{21}{60}=\frac{7}{20}=\frac{3,5}{10}=0,35hr\)
so the time that takes the express train to travel 600km is the time traveled+the time stoped. 6+0,35=6,35hr
now for the local train
R*T=D
50*6,35=317,5
in this case, opposite to the first case, we have to subtract the stops of the local train. We know that every 25km the train made a stop of 1 min. 317,5 is aprox 318 so \(\frac{318}{25}=\frac{63}{5}=13 min.aprox\)
Now from total time take out the \(13 min=\frac{13}{60}hr\).
\(6,35hr-\frac{13}{60}hr=6,14 hr\). This is the time were the local train was in movement.
so again R*T=d
50*6,14=307 aprox
IMO C
17 Jun 2024, 04:05
Kudos
Bookmarks
Express Train 100 km/hr :
600km / 75 km = 8 Runs of 75km each
Time taken = 8*(75/100) + 7 halts of 3 min each in between
= 6 hrs + 21 mins
Passenger Train @ 50km/hr :
Distance covered in 6 hr 21 min = ?
Each stretch of 25 km (given) => 25/50 hr = 30 hr run each time
When broken 6 hr 21 min = { 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 9 } min = (12*30) + 12* (1 min halt) + (21-12 = 9) min
Therefore, Distance covered = 12* (0.5*50) + (9/60)*50 = 300 + 7.5
= 307.5 kms
Ans: C
600km / 75 km = 8 Runs of 75km each
Time taken = 8*(75/100) + 7 halts of 3 min each in between
= 6 hrs + 21 mins
Passenger Train @ 50km/hr :
Distance covered in 6 hr 21 min = ?
Each stretch of 25 km (given) => 25/50 hr = 30 hr run each time
When broken 6 hr 21 min = { 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 30+1+ 9 } min = (12*30) + 12* (1 min halt) + (21-12 = 9) min
Therefore, Distance covered = 12* (0.5*50) + (9/60)*50 = 300 + 7.5
= 307.5 kms
Ans: C
