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21 Nov 2020, 20:25
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
44% (02:16) correct
56%
(02:19)
wrong
based on 59
sessions
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Not Attempted Yet
An iron ball of diameter 6 inches is placed in a cylindrical beaker containing some water (enough to completely immerse the ball).
What is the rise in water level (in inches), if the diameter of the beaker is 1 feet and it's height is 10 inches?
Note: 12 inches = 1 foot
A. 0.5
B. 1.0
C. 1.5
D. 2.0
E. 3.0
What is the rise in water level (in inches), if the diameter of the beaker is 1 feet and it's height is 10 inches?
Note: 12 inches = 1 foot
A. 0.5
B. 1.0
C. 1.5
D. 2.0
E. 3.0
OA: B
santosh93
Joined: 07 Jul 2020
Last visit: 19 May 2022
Posts: 47
Given Kudos: 340
Location: India
Schools: NTU (D) MBS'23 (D) Warwick "23 (D) ISB '23 (D)
GRE 1: Q169 V152
GPA: 3.94
WE:Research (Manufacturing)
21 Nov 2020, 22:15
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As the answer is requested in inches convert all the data into inches
Diameter of iron ball = 6 inches
radius= 3 inches
Diameter of beaker = 1feet
= 12 inches
beaker radius = 6inches
Height of beaker = 10inches
Amount of water displaced = Volume of the object immersed in water
The volume of ball = 4π \((r)^2\)
= 4π \((3)^2\)
= 36π
Rise in water level in cylindrical beaker = The volume taken by the iron ball immersed
π \((r)^2\)h = 36π
π \((6)^2\)h = 36π
h = 1
The answer is B
Diameter of iron ball = 6 inches
radius= 3 inches
Diameter of beaker = 1feet
= 12 inches
beaker radius = 6inches
Height of beaker = 10inches
Amount of water displaced = Volume of the object immersed in water
The volume of ball = 4π \((r)^2\)
= 4π \((3)^2\)
= 36π
Rise in water level in cylindrical beaker = The volume taken by the iron ball immersed
π \((r)^2\)h = 36π
π \((6)^2\)h = 36π
h = 1
The answer is B
18 Sep 2021, 10:00
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santosh93
Volume should be 4/3 pi r^3.
your formula is working here because the r is 3
